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VLD [36.1K]
3 years ago
9

What is the volume, in milliliters, occupied by 30.07 g of an object of density equal to

Chemistry
1 answer:
den301095 [7]3 years ago
3 0

Answer:

\boxed {\tt 20.317567567568 \ mL}

Explanation:

The density formula is:

d=\frac{m}{v}

Let's rearrange the formula for v. the volume. Multiply both sides by v, then divide by d.

d*v=\frac{m}{v}*v

d*v=m

\frac{d*v}{d}=\frac{m}{d}

v=\frac{m}{d}

The volume can be found by dividing the mass by the density. The mass of the object is 30.07 grams and the density is 1.48 grams per milliliter.

m= 30.07 \ g\\d= 1.48 \ g/mL

v=\frac{30.07 \ g}{1.48 \ g/mL}

Divide. Note, when dividing, the grams, or g will cancel out.

v= \frac{30.07}{1.48 \ mL}

v=20.317567567568 \ mL

The volume of the object is 20.317567567568 milliliters.

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Please answer this question ASAP. This is on a homework assignment that is due tonight!! Thank you in advance! A voltaic cell em
worty [1.4K]
Ecell = E°cell - RT/vF * lnQ

R is the gas constant: 8.3145 J/Kmol
T is the temperature in kelvin: 273.15K = 0°C, 25°C = 298.15K
v is the amount of electrons, which in your example seems to be six (I'm not totally sure)
F is the Faradays constant: 96485 J/Vmol (not sure about the mol)
Q is the concentration of products divided by the concentration of reactants, in which we ignore pure solids and liquids: [Mg2+]³ / [Fe3+]²

Standard conditions is 1 mol, at 298.15K and 1 atm

To find E°cell, you have to look up the reduction potensials of Fe3+ and Mg2+, and solve like this:

E°cell = cathode - anode

Cathode is where the reduction happens, so that would be the element that recieves electrons. Anode is where the oxidation happens, so that would be the element that donates electrons. In your example Fe3+ recieves electrons, and should be considered as cathode in the equation above. 

When you have found E°cell, you can just solve with the numbers I gave you. 
7 0
3 years ago
Read 2 more answers
3.
Anastasy [175]

Answer:

I think it's letter B

Explanation:

Hope it helps correct if I'm wrong

7 0
3 years ago
4. If an experimental value for a given observation was 415 nm while the theoretical value
Alex

Answer: % error of observation is 4.77%

Explanation:

Given:

Observation value = 415nm

theoretical value= 435.8nm

Percent error of observation = theoretical value- observation value/ theoretical value x 100 %

= 435.8-415/435.8= 0.04772 x 100 = 4.77%

therefore % error of observation is 4.77%

7 0
3 years ago
Is it possible to have a bent molecule without a molecular dipole?
s2008m [1.1K]

Answer:

no but that is what we were taught

3 0
3 years ago
A sample of gas in which [h2s] = 3.50 m is heated to 1400 k in a sealed vessel. after chemical equilibrium has been achieved, wh
Bond [772]
The value of Kc for the thermal decomposition of H₂S is 2.2 x 10⁻⁴ at 1400 K:
                        2 H₂S(g) ↔     2 H₂(g) + S₂(g)
initial                  3.5 M               0           0
at equilibrium     3.5 M - 2x       2x          x
Kc             = [S₂][H₂]² / [H₂S]² 
2.2 X 10⁻⁴ = x(2x)² / (3.5 - 2x)²
2.2 x 10⁻⁴ = 4 x³ / (3.5)² Assuming x <<<<< 3.5
x = 0.088
Thus [H₂S] = 3.324 M
6 0
3 years ago
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