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Vlad [161]
3 years ago
7

how much energy is required to heat an iron nail with a mass of 25.5 grams from 65° until it becomes red hot at 720 degrees Cels

ius
Chemistry
1 answer:
Kay [80]3 years ago
3 0
2273.6 Joules that’s your answer
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The PRODUCT is found on the right side of the arrow in a chemical reaction.
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Scientific explanations are not always based on empirical evidence <br><br> True or false?
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True some explanations are not always based on empirical evidence
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DirectionsAnswer each question in the spaceQuestion1. Why does a neutral atom haveno overall charge?2. What determines the charg
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7 0
3 years ago
A) Find the gas speed of sulfur dioxide at 100.0 degrees Celsius? ______________
gtnhenbr [62]

a. 381.27 m/s

b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide

<h3>Further explanation</h3>

Given

T = 100 + 273 = 373 K

Required

a. the gas speedi

b. The rate of effusion comparison

Solution

a.

Average velocities of gases can be expressed as root-mean-square averages. (V rms)  

\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}

R = gas constant, T = temperature, Mm = molar mass of the gas particles  

From the question  

R = 8,314 J / mol K  

T = temperature  

Mm = molar mass, kg / mol  

Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol

\tt v=\sqrt{\dfrac{3\times 8.314\times 373}{0.064} }\\\\v=381.27~m/s

b. the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

M₁ = molar mass sulfur dioxide = 64

M₂ =  molar mass nitrogen triodide = 395

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{395}{64} }=\dfrac{20}{8}=2.5

the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide

4 0
3 years ago
1. What temperature is equivalent to 32°F?
Vlad1618 [11]

Answer:

0 Celsius

Explanation:

its 0 degrees C

4 0
3 years ago
Read 2 more answers
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