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Anton [14]
3 years ago
15

Now, imagine a cow who eats grass (which is mostly non- digestible cellulose) all day long. How does a cow get any energy out of

that cellulose?
Chemistry
1 answer:
gavmur [86]3 years ago
8 0
<span>This makes a whole new energy source available to the cow. There's a lot of energy in cellulose, but most animals are simply unable to digest it because they don't have the necessary enzymes. That's where the microbes come in. Hope this helped! :)
</span>
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state two methods that can be used to prepare chlorine from rock salt.write an equation in each case​
Levart [38]

Answer:

electrolysis of brine

Explanation:

Rock salt deposits are usually mined; occasionally water is pumped down, and brine which contain 25 percent of sodium chloride is found

so d brine is electrolyzed to produce chlorine

7 0
2 years ago
When heat is applied to water a 10 degrees Celsius, what does the energy transform into?
LUCKY_DIMON [66]

Answer:

Gas

Explanation:

This is kind of like the process of evaporating

5 0
3 years ago
To decrease the rate of reaction you would ... *
STALIN [3.7K]
Answer: it’s number 2 add a catalyst

Hopefully this helped :)
4 0
3 years ago
Read 2 more answers
How is copper sulphate different to copper sulphide in terms of the elments it contains
son4ous [18]

Answer:

An Element is a substance made up of only one type of atom as like gold, copper, oxygen, etc.

Copper sulphate with molecular formula (CuSO_4), the elements are copper, sulphur and oxygen. It is formed by combination of Cu^{2+} cation and SO_4^{2-} anion.

Copper sulphide with molecular formula (CuS), the elements are copper and sulphur. It is formed by combination of Cu^{2+} cation and S^{2-} anion.

6 0
3 years ago
How many liters of 1.75 M solution could be made using 35 grams of NaCl?
dolphi86 [110]
Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)

Formula:
M =  \frac{m}{MM*V}

Solving:
M = \frac{m}{MM*V}
1.75 =  \frac{35}{58.44*V}
1.75*58.44V = 35
102.27V = 35
V =  \frac{35}{102.27}
\boxed{\boxed{V \approx 0.34\:L}}\end{array}}\qquad\quad\checkmark
3 0
3 years ago
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