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Anton [14]
3 years ago
15

Now, imagine a cow who eats grass (which is mostly non- digestible cellulose) all day long. How does a cow get any energy out of

that cellulose?
Chemistry
1 answer:
gavmur [86]3 years ago
8 0
<span>This makes a whole new energy source available to the cow. There's a lot of energy in cellulose, but most animals are simply unable to digest it because they don't have the necessary enzymes. That's where the microbes come in. Hope this helped! :)
</span>
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How many moles are in a 62.5-g sample of potassium nitrate (KNO3)?
Reil [10]

Answer:25.3 g of KNO₃ contain 0.25 moles.

Explanation:

7 0
2 years ago
Какая масса хлора и какое количество вещества необходимо для реакции с 12г магния при получении хлорида магния?
Naddika [18.5K]
Mg + Cl₂ = MgCl₂M(Mg) = 24г/моль  m 1 моль Mg = 24 г.По условию задачи дано 12г. Mg  Количество вещества n(Mg) =12÷24=0,5 мольРассуждаем: по уравнению реакции  с 1 моль магния реагирует 1 моль хлора, следовательно с 0,5 моль будет реагировать 0,5 моль хлора.1 моль хлора при н.у. занимает объем 22,4л. , тогда 0,5 моль хлора займет:0,5х22,4л.= 11,2л. Ответ: Для взаимодействии 12 г.  магния потребуется 11,2 л. хлора.
7 0
3 years ago
Saturated fats are typically liquid at room temperature. saturated fats are typically liquid at room temperature.
dmitriy555 [2]
False, saturated fats like butter or coconut oil are typically solid at room temperature.
7 0
3 years ago
Question 1 (1 point)
Sergio [31]

Answer:

Sonar Pulse

Explanation:

5 0
2 years ago
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The mass defect for the formation of lithium-6 is 0.0343 g/mol. The binding energy for lithium-6 nuclei is ________ kJ/mol. Ente
Sholpan [36]

<u>Answer:</u> The binding energy for lithium-6 nuclei is 3.09 E+11

<u>Explanation:</u>

Binding energy is defined as the energy which holds the nucleus together. It is basically the product of mass defect and the square of the speed of light.

This energy is calculated by using Einstein's equation, which is:

E=\Delta mc^2

where,

E = Binding energy of the atom

Delta m = Mass defect = 0.0343g/mol = 0.0343\times 10^{-3}kg/mol     (Conversion factor: 1kg=10^3g )

c = speed of light = 3\times 10^8m/s

Putting values in above equation, we get:

E=0.0343\times 10^{-3}kg/mol\times (3\times 10^8m/s)^2

E=3.09\times 10^{14}J/mol=3.09\times 10^{11}kJ/mol     (Conversion factor: 1kJ=10^3J )

Hence, the binding energy for lithium-6 nuclei is 3.09 E+11

7 0
2 years ago
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