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3 years ago

HELP QUICK WILL MARK AS BRAINLEST!!!

Physics

1 answer:

ohaa [14]3 years ago

8 0

The answer is c hope it helps

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Fantom [35]

Answer:

Explanation:

Intensity of sound = sound energy emitted by source / 4 π d² , where d is distance of the source .

A )

Intensity of sound at 1 m distance = 60 /4 π d²

d = 1 m

Intensity of sound at 1 m distance = 60 /(4 π 1²)

= 4.78 W m⁻² s⁻¹

B )

Intensity of sound at 1.5 m distance = 60 /4 π d²

d = 1.5 m

Intensity of sound at 1 m distance = 60 /(4 π 1.5²)

= 2.12 W m⁻² s⁻¹

C )

Intensity of sound due to 4 speakers at 1.5 m distance = 4 x 60 /4 π d²

d = 1.5 m

= 4 x 60 /(4 π 1.5²)

= 8.48 W m⁻² s⁻¹

D )

Intensity of sound due to .06 W speaker must be 10⁻¹² W s ⁻² . Let the distance be d .

.06 /4 π d² = 10⁻¹²

d² = .06 /4 π 10⁻¹²

d = 6.9 x 10⁴ m .

7 0

3 years ago

The space between molecules is called what? Need this for a test

alexdok [17]

Answer:

voids

Explanation:

7 0

3 years ago

What are two prevention methods of cardiovascular disease

earnstyle [38]

Answer:

i think its c and d

(btw thats my best guess)

Explanation:

3 0

2 years ago

Read 2 more answers

Plsss plsss plsss helppppp ASAP thank u ❤️

Aleonysh [2.5K]

Answer:

7. (D) uniformly accelerated vertical motion

8. (A) zero

9. (A) zero

10. (C) parabolic

5 0

2 years ago

Read 2 more answers

The driver of a car going 96.0 km/h suddenly sees the lights of a barrier 39.0 m ahead. It takes the driver 0.75 s to apply the

arsen [322]

Answer:

21.42m/S

Explanation:

Hello!

To solve this problem we must perform the following steps.

1. Find the distance traveled from until the driver reacts, this is achieved using the equation for constant speed movement.

X1=VT

where

x= distance traveled

v=initial speed

T=time=0.75s

X1=0.75Vo

we must take into account that the total distance is the sum of the distance at which the pilot reacts (x1) and when it starts to decelerate (x2)

39=0.75Vo+X2

X2=39-0.75Vo

2. Now we use the equation that defines a movement with constant acceleration.

$Vo =\sqrt{Vf^2 - 2(a)(x2)}$

where

Vf = final speed=0m/s

Vo = Initial speed

A = acceleration =-10m/s2

X2 = displacement

now we use the ecuation of step 1

$Vo =\sqrt{Vf^2 - 2(a)(39-0.75Vo)}$

solving

$Vo =\sqrt{0 - 2(-10))(39-0.75Vo)}\\Vo^2=780-15Vo\\Vo^2+15Vo-780=0$

Now we solve the quadratic equation and find the value of Vo

the solutions are 21.42m/S, -36.41m/S

as the speed must be positive we conclude that the answer is 21.42m/S

6 0

3 years ago