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kumpel [21]
3 years ago
15

Brainliest giveaway just like my questions ​

Engineering
2 answers:
mafiozo [28]3 years ago
8 0

Answer:

i like your question

Explanation:

amm18123 years ago
4 0

Answer:.

Explanation:

Love it

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Which type of Artificial Intelligence (AI) can repeatedly perform tasks of limited scope?
seraphim [82]

Narrow AI is the type of Artificial Intelligence (AI) can repeatedly perform tasks of limited scope.

  • Natural Language Understanding (NLU) is used to describe extracting information from unstructured text using algorithms.

<h3>What is Narrow AI ?</h3>

This is known to be a form or a type of AI that is said to be able to carry out a dedicated task as a result of its intelligence.

Note that Narrow AI is the type of Artificial Intelligence (AI) can repeatedly perform tasks of limited scope.

  • Natural Language Understanding (NLU) is used to describe extracting information from unstructured text using algorithms.

Learn more about Artificial Intelligence from

brainly.com/question/25523571

#SPJ1

7 0
2 years ago
Your program must output each student’s name in the form: last name followed by a comma, followed by a space, followed by the fi
Reptile [31]

Answer:

#include <iostream>

#include <string>

#include <fstream>

using namespace std;

char getStudentGrade(int testScore);

//Declare constant max students in file 10

const int maxStudents = 10;

struct StudentType

{

  string studentFName;

  string studentLName;

  int testScore;

  char grade;

};

void readStudentData(StudentType students[]){

  int i = 0;

 

  ifstream infile;

  infile.open("inputStudentData.txt");

 

 

  while (!infile.eof())

  {

   infile >> students[i].studentFName;

   infile >> students[i].studentLName;

   infile >> students[i].testScore;

   students[i].grade = getStudentGrade(students[i].testScore);

      i++;

  }

}

char getStudentGrade(int testScore){

  char grade;

  if(testScore >= 80) {

      grade = 'A';      

  }

  else if(testScore >= 60) {

      grade = 'B';

  }

  else if(testScore >= 50) {

      grade = 'C';  

  }

  else if(testScore >= 40) {

      grade = 'D';      

  }

  else {

      grade = 'F';  

  }

  return grade;

}

int main()

{

 

  StudentType students[10];

 

  readStudentData(students);

 

  for(int i=0;i<maxStudents;i++) {

      students[i].grade = getStudentGrade(students[i].testScore);

  }

 

  for(int i=0; i<maxStudents; i++){    

      cout << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

  }

  ofstream outputFile;

  outputFile.open ("outputStudentData.txt");

 

  for(int i=0; i<maxStudents; i++){    

      outputFile << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

  }

  outputFile.close();

  return 0;

}

3 0
4 years ago
Design an algorithm for computing √n
a_sh-v [17]
Positive integer n design an algorithm
8 0
2 years ago
A plant manager randomly selects a can of peas from the assembly line and records whether or not the can's label is properly att
love history [14]

Complete Question

For each of the following experiments, identify the counting rule that is relevant for determining the number of experimental outcome.Then use the counting rules to determine the number of experimental outcome

First Experiment

A plant manager randomly selects a can of peas from the assembly line and records whether or not the can's label is properly attached , followed by the weight of the can (as less than 14 ounces, exactly 14, or more than 14 ounces).

Which is the correct Counting rule?

1) Multiple-Step Experiments

2) Permutations

3) Combinations

What is the Number of Experimental Outcomes?

Second Experiment

Three branches (A,B, and C) of a bank have open manager positions. Three home-office employees from a pool of five are randomly selected to fill the manager positions. The first home-office employee selected becomes the manager of branch A, the second becomes the manager of branch B, and the third becomes manager of branch C.

Which is the correct Counting rule?

1) Multiple-Step Experiments

2) Permutations

3) Combinations

What is the Number of Experimental Outcomes?

Third Experiment

A stockbroker forms a stock portfolio for a client by randomly selecting three stock from a pool of five.

Which is the correct Counting rule?

1) Multiple-Step Experiments

2) Permutations

3) Combinations

What is the Number of Experimental Outcomes?

Answer:

First Experiment

Counting rule: Multiple-Step Experiments

Number of Experimental Outcomes: 6

Second Experiment

Counting rule: Permutations

Number of Experimental Outcomes: 60

Third Experiment

Counting rule: Combinations

Number of Experimental Outcomes: 10

Explanation:

The explanation of the first experiment is on the first uploaded image

For the second experiment the counting rule is  permutation because from the experiment we can see that the order of selection  is important

To obtain the Number of Experimental Outcomes:

         We have:  

                         5p_{3} = \frac{5!}{2!}

                               = \frac{5*4*3*2!}{2!}

                              = 60

For the third experiment the the counting rule is combination because the order of selection is not important

To obtain the Number of Experimental Outcomes:

         We have:  

                         5C_{3} =\frac{5!}{3!2!}

                                = 10

   

4 0
3 years ago
To compute the energy used by a motor, multiply the power that it draws by the time of operation. Con- sider a motor that draws
ehidna [41]

Answer:

E=52000Hp.h

E=38724920Wh

E=1.028x10^11 ftlb

Explanation:

To solve this problem you must multiply the engine power by the time factor expressed in h / year, to find this value you must perform the conventional unit conversion procedure.

Finally, when you have the result Hp h / year you convert it to Ftlb and Wh

E=(12.5hp)(\frac{16h}{day} )(\frac{5 days}{week} )(\frac{52week}{year} )\\

E=52000Hp.h

E=52000Hp.h(\frac{744.71Wh}{Hp.h} )\\

E=38724920Wh

E=52000Hph(\frac{1977378.4  ft lb}{1Hph}

E=1.028x10^11 ftlb

3 0
3 years ago
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