Answer: it’s very bad behavior and can be dangerous
Explanation:
Answer:
a) 4.7 kΩ, +/- 5%
b) 2.0 MΩ, +/- 20%
Explanation:
a) If the resistor has the following combination of color bands:
1) Yellow = 1st digit = 4
2) Violet = 2nd digit = 7
3) Red = multiplier = 10e2
4) Gold = tolerance = +/- 5%
this means that the resistor has 4700 Ω (or 4.7 kΩ), with 5% tolerance.
b) Repeating the process for the following combination of color bands:
1) Red = 1st digit = 2
2) Black = 2nd digit = 0
3) Green = multiplier = 10e5
4) Nothing = tolerance = +/- 20%
This combination represents to a resistor of 2*10⁶ Ω (or 2.0 MΩ), with +/- 20% tolerance.
Answer:
The fluid level difference in the manometer arm = 22.56 ft.
Explanation:
Assumption: The fluid in the manometer is incompressible, that is, its density is constant.
The fluid level difference between the two arms of the manometer gives the gage pressure of the air in the tank.
And P(gage) = ρgh
ρ = density of the manometer fluid = 60 lbm/ft³
g = acceleration due to gravity = 32.2 ft/s²
ρg = 60 × 32.2 = 1932 lbm/ft²s²
ρg = 1932 lbm/ft²s² × 1lbf.s²/32.2lbm.ft = 60 lbf/ft³
h = fluid level difference between the two arms of the manometer = ?
P(gage) = 9.4 psig = 9.4 × 144 = 1353.6 lbf/ft²
1353.6 = ρg × h = 60 lbf/ft³ × h
h = 1353.6/60 = 22.56 ft
A diagrammatic representation of this setup is presented in the attached image.
Hope this helps!
Answer:
![D_o=11.9inch](https://tex.z-dn.net/?f=D_o%3D11.9inch)
Explanation:
From the question we are told that:
Thickness ![T=0.5](https://tex.z-dn.net/?f=T%3D0.5)
Internal Pressure![P=2.2Ksi](https://tex.z-dn.net/?f=P%3D2.2Ksi)
Shear stress ![\sigma=12ksi](https://tex.z-dn.net/?f=%5Csigma%3D12ksi)
Elastic modulus ![\gamma= 35000](https://tex.z-dn.net/?f=%5Cgamma%3D%2035000)
Generally the equation for shear stress is mathematically given by
![\sigma=\frac{P*r_1}{2*t}](https://tex.z-dn.net/?f=%5Csigma%3D%5Cfrac%7BP%2Ar_1%7D%7B2%2At%7D)
Where
r_i=internal Radius
Therefore
![12=\frac{2.2*r_1}{2*0.5}](https://tex.z-dn.net/?f=12%3D%5Cfrac%7B2.2%2Ar_1%7D%7B2%2A0.5%7D)
![r_i=5.45](https://tex.z-dn.net/?f=r_i%3D5.45)
Generally
![r_o=r_1+t](https://tex.z-dn.net/?f=r_o%3Dr_1%2Bt)
![r_o=5.45+0.5](https://tex.z-dn.net/?f=r_o%3D5.45%2B0.5)
![r_o=5.95](https://tex.z-dn.net/?f=r_o%3D5.95)
Generally the equation for outer diameter is mathematically given by
![D_o=2r_o](https://tex.z-dn.net/?f=D_o%3D2r_o)
![D_o=11.9inch](https://tex.z-dn.net/?f=D_o%3D11.9inch)
Therefore
Assuming that the thin cylinder is subjected to integral Pressure
Outer Diameter is
![D_o=11.9inch](https://tex.z-dn.net/?f=D_o%3D11.9inch)