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julia-pushkina [17]
3 years ago
8

Why do giant stars become planetary nebulas while supergiant stars become supernovas when their nuclear fusion slows and is over

come by gravity?
Supergiant stars do not have enough mass to generate the gravity necessary to cause a planetary nebula.


Supergiant stars are too massive to have planets and thus do not have planetary nebulas.


Giant stars do not have enough mass to generate the gravity necessary to cause a supernova.


Supernovas require binary star systems to form and giant stars do not form binary star systems.
Engineering
1 answer:
sashaice [31]3 years ago
3 0

The reason why giant stars become planetary nebulas is  Supergiant stars do not have enough mass to generate the gravity necessary to cause a planetary nebula.

<h3>Why do giant stars become planetary nebulae?</h3>

A planetary nebula is known to be formed or created by a dying star. A red giant is known to be unstable and thus emit pulses of gas that is said to form a sphere around the dying star and thus they are said to  be ionized by the ultraviolet radiation that the star is known to releases.

Learn more about  giant stars from

brainly.com/question/27111741

#SPJ1

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YO CUTIE! HELP MEEEEEE! Hazardous waste is a category that includes all of the following EXCEPT
madam [21]

your answer should be <u>B. Soluble</u>

3 0
3 years ago
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What best describes the relationship between missionaries and Native Americans?
Vlad [161]

Answer:

Missionaries taught the Native Americans to read but allowed them to keep their customs. Native Americans and missionaries fought in battles

Explanation:

sorry if this doesn't help u but i hope it does!

6 0
3 years ago
A product whose total work content time = 50 min is assembled on a manual production line at a rate of 24 units per hour. From p
valentinak56 [21]

Answer:

a)Cycle time = 2.37 min

b)Numbers of workers =21

c)Stations on the line =24

Explanation:

Given that

Total work content time(TWC) = 50 min

Production rate Rp= 24 units/hr

manning level will be close =1.5

Line balancing efficiency =0.94

a)

Cycle time

T_c=\dfrac{60E}{R_P}

T_c=\dfrac{60\times 0.95}{24}

Cycle time = 2.37 min

b)

Numbers of workers ,W

W=\dfrac{TWC}{T_c}

W=\dfrac{50}{2.37}

W= 21

Numbers of workers =21

c)

Stations on the line(n)

Lets find service time Ts

Ts = Cycle time -  Time for repositioning

Ts = Tc- Tr

Ts= 2.37  - 9/ 60 min

Ts= 2.22 min

We  know that efficiency

\eta=\dfrac{TWC}{n.T_s}

0.94=\dfrac{50}{n\times 2.22}

n=23.94  ⇒n=24

n=24

Stations on the line =24

7 0
3 years ago
Which of the following is true about silicosis?
user100 [1]

Answer:

D. The damage it causes is irreversible

Explanation:

Silicosis is a long term lung disease caused by crystalline silica dust inhalation. There is no cure, and once the damage is done it cannot be reversed.

------------------

Like stated above, the damage is irreversible. Option A is incorrect.

Construction workers are constantly moving to build whatever they're working on. The disease will make it hard to breathe and will have a heavy effect on their lungs, preventing them from properly doing their jobs. Additionally, it's possible to get the disease from this job since you're constantly inhaling dust particles.

Silicosis does major damage to the lungs. The dust particles are attacked by the immune system which causes inflammation and eventually leads to areas of hardened and scarred lung tissue.

Thus, the best option is D.

hope this helps :)

5 0
2 years ago
Refrigerant-134a enters an adiabatic compressor as saturated vapor at -24°C and leaves at 0.8 MPa and 60°C. The mass flow rate o
Leni [432]

Answer:

(a) The power input to the compressor: \dot{W}=73.07 kJ/s = 73.07 kW

(b) The volume flow rate of the refrigerant at the compressor inlet: \dot{v}=0.209 m^{3}/s

Explanation:

(a)

We need to check the values of enthalpy (as we have an open system) for both states, being the inlet, state 1 and the outlet, state 2. We will know these values by checking the vapor charts of R134a, I used the ones found in Thermodynamics of Cengel, 7th edition.

Then, our values are:

h_{1}=235.92kJ/kg\\h_{2}=296.81kJkg

Now we proceed to know the work with the following expression:

\dot{W}=\dot{m}(h_{2}-h_{1})

Now we replace values and our result is:

\dot{W}=73.07 kJ/s = 73.07 kW

(b)

To know the volume rate at the compressor inlet, we need to know the specific volume in that phase, as we have that is saturated and at -24°C, we can read our table:

\nu=0.1739m^{3}/kg

With our specific volume and the mass rate, we can calculate the volume rate:

\dot{v}=\nu * \dot{m}\\\dot{v}=0.209 m^{3}/s

6 0
4 years ago
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