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steposvetlana [31]
3 years ago
11

A plant manager randomly selects a can of peas from the assembly line and records whether or not the can's label is properly att

ached , followed by the weight of the can (as less than 14 ounces, exactly 14, or more than 14 ounces).
Counting rule: Multiple-Step Experiments, permutations, or combinations?

Number of Experimental Outcomes?

Three branches (A,B, and C) of a bank have open manager positions. Three home-office employees from a pool of five are randomly selected to fill the manager positions. The first home-office employee selected becomes the manager of branch A, the second becomes the manager of branch B, and the third becomes manager of branch C.

Counting rule: Multiple-Step Experiments, permutations, or combinations?

Number of Experimental Outcomes?

A stockbroker forms a stock portfolio for a client by randomly selecting three stock from a pool of five.

Counting rule: Multiple-Step Experiments, permutations, or combinations?

Number of Experimental Outcomes?

Engineering
1 answer:
love history [14]3 years ago
4 0

Complete Question

For each of the following experiments, identify the counting rule that is relevant for determining the number of experimental outcome.Then use the counting rules to determine the number of experimental outcome

First Experiment

A plant manager randomly selects a can of peas from the assembly line and records whether or not the can's label is properly attached , followed by the weight of the can (as less than 14 ounces, exactly 14, or more than 14 ounces).

Which is the correct Counting rule?

1) Multiple-Step Experiments

2) Permutations

3) Combinations

What is the Number of Experimental Outcomes?

Second Experiment

Three branches (A,B, and C) of a bank have open manager positions. Three home-office employees from a pool of five are randomly selected to fill the manager positions. The first home-office employee selected becomes the manager of branch A, the second becomes the manager of branch B, and the third becomes manager of branch C.

Which is the correct Counting rule?

1) Multiple-Step Experiments

2) Permutations

3) Combinations

What is the Number of Experimental Outcomes?

Third Experiment

A stockbroker forms a stock portfolio for a client by randomly selecting three stock from a pool of five.

Which is the correct Counting rule?

1) Multiple-Step Experiments

2) Permutations

3) Combinations

What is the Number of Experimental Outcomes?

Answer:

First Experiment

Counting rule: Multiple-Step Experiments

Number of Experimental Outcomes: 6

Second Experiment

Counting rule: Permutations

Number of Experimental Outcomes: 60

Third Experiment

Counting rule: Combinations

Number of Experimental Outcomes: 10

Explanation:

The explanation of the first experiment is on the first uploaded image

For the second experiment the counting rule is  permutation because from the experiment we can see that the order of selection  is important

To obtain the Number of Experimental Outcomes:

         We have:  

                         5p_{3} = \frac{5!}{2!}

                               = \frac{5*4*3*2!}{2!}

                              = 60

For the third experiment the the counting rule is combination because the order of selection is not important

To obtain the Number of Experimental Outcomes:

         We have:  

                         5C_{3} =\frac{5!}{3!2!}

                                = 10

   

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Transcript
posledela

Answer:

O is truse is the best answer hhahahha

Explanation:

8 0
3 years ago
A hydraulic jump is induced in an 80 ft wide channel.The water depths on either side of the jump are 1 ft and 10 ft.Please calcu
krek1111 [17]

Answer:

a) 42.08 ft/sec

b) 3366.33 ft³/sec

c) 0.235

d) 18.225 ft

e) 3.80 ft

Explanation:

Given:

b = 80ft

y1 = 1 ft

y2 = 10ft

a) Let's take the formula:

\frac{y2}{y1} = \frac{1}{5} * \sqrt{1 + 8f^2 - 1}

10*2 = \sqrt{1 + 8f^2 - 1

1 + 8f² = (20+1)²

= 8f² = 440

f² = 55

f = 7.416

For velocity of the faster moving flow, we have :

\frac{V_1}{\sqrt{g*y_1}} = 7.416

V_1 = 7.416 *\sqrt{32.2*1}

V1 = 42.08 ft/sec

b) the flow rate will be calculated as

Q = VA

VA = V1 * b *y1

= 42.08 * 80 * 1

= 3366.66 ft³/sec

c) The Froude number of the sub-critical flow.

V2.A2 = 3366.66

Where A2 = 80ft * 10ft

Solving for V2, we have:

V_2 = \frac{3666.66}{80*10}

= 4.208 ft/sec

Froude number, F2 =

\frac{V_2}{g*y_2} = \frac{4.208}{32.2*10}

F2 = 0.235

d) El = \frac{(y_2 - y_1)^3}{4*y_1*y_2}

El = \frac{(10-1)^3}{4*1*10}

= \frac{9^3}{40}

= 18.225ft

e) for critical depth, we use :

y_c = [\frac{(\frac{3366.66}{80})^2}{32.2}]^1^/^3

= 3.80 ft

7 0
3 years ago
Read 2 more answers
An ideal gas initially at 300 K and 1 bar undergoes a three-step mechanically reversible cycle in a closed system. In step 12, p
Veseljchak [2.6K]

Answer:

Ts =Ta E)- 300(

569.5 K

5

Q12-W12 = -4014.26

Mol

AU2s = Q23= 5601.55

Mol

AUs¡ = Ws¡ = -5601.55

Explanation:

A clear details for the question is also attached.

(b) The P,V and T for state 1,2 and 3

P =1 bar Ti = 300 K and Vi from ideal gas Vi=

10

24.9x10 m

=

P-5 bar

Due to step 12 is isothermal: T1 = T2= 300 K and

VVi24.9 x 10x-4.9 x 10-3 *

The values at 3 calclated by Uing step 3l Adiabatic process

B-P ()

Since step 23 is Isochoric: Va =Vs= 4.99 m* and 7=

14

Ps-1x(4.99 x 103

P-1x(29x 10)

9.49 barr

And Ts =Ta E)- 300(

569.5 K

5

(c) For step 12: Isothermal, Since AT = 0 then AH12 = AU12 = 0 and

Work done for Isotermal process define as

8.314 x 300 In =4014.26

Wi2= RTi ln

mol

And fromn first law of thermodynamic

AU12= W12 +Q12

Q12-W12 = -4014.26

Mol

F'or step 23 Isochoric: AV = 0 Since volume change is zero W23= 0 and

Alls = Cp(L3-12)=5 x 8.311 (569.5 - 300) = 7812.18-

AU23= C (13-72) =5 x 8.314 (569.3 - 300) = 5601.53

Inol

Now from first law of thermodynamic the Q23

AU2s = Q23= 5601.55

Mol

For step 3-1 Adiabatic: Since in this process no heat transfer occur Q31= 0

and

AH

C,(T -Ts)=x 8.314 (300- 569.5)= -7842.18

mol

AU=C, (T¡-T)= x 8.314 (300

-5601.55

569.5)

mol

Now from first law of thermodynamie the Ws1

J

mol

AUs¡ = Ws¡ = -5601.55

3 0
3 years ago
What is the worlds fastest car
Aneli [31]

Answer:

Thrust SSC

Explanation:

You can look it up

3 0
3 years ago
Read 2 more answers
Explain the working of McLeod gauge for measurement of very low pressure.
AfilCa [17]

Explanation:

McLeod gauge:

  It is used to measure very low pressure of gas.It measure gas pressure by the help of mercury(Hg).it measure absolute pressure of gas.

McLeod gauge on the principle of Boyle's law.Boyle's law state that ,at constant temperature the pressure of gas is directly proportional to its  volume.From Boyle's law

P_1V_1=P_2V_2

A sample of gas is taken from vacuum then its pressure is measured by help  Hg.

4 0
4 years ago
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