Answer:
t = 3.0s
Explanation:
U = 2.0m/s , V = 0 (stop) , S = 3m , t =?
From V^2 - U^2 = 2aS
=) a = -4/6 = -0.667m/s^2
Now again by V-U = at
We have t = -U/a = 2/0.667 = 3s
Required time is t = 3.0s
So here, you're looking for distance. The formula is D=vt+1/2at^2.
Lets plug in the informations.
10 m/s is our v (initial velocity)
5 second is out t(time)
3.2 m/s is our a(acceleration)
10m/s(5)+1/2(3.2m/s+5^2)
50m/s+1/2(28.2)
50m/s+14.1
Answer =64.1 m
Glad to help you out buddy. Let me know if you need help.
None of the choices is correct.
If two runners take the same amount of time to run a mile,
they have the same average speed. But their velocities
are not the same unless both runners begin and end their
run at the same points.
Speed is (distance covered) divided by (time to cover the distance).
Velocity is not. It's something different.
'Velocity' is not just a bigger word for 'speed'.
components of the speed of the coin is given as
now the time taken by the coin to reach the plate is given by
now in order to find the height
so it is placed at 1.52 m height
Density= mass/volume
in this case density= 1.1g
and the volume = 40 cm^3
so
1.1=40/mass
mass=40/1.1
mass=36.4
