A child height can be very tall or short
Explanation:
We have,
Speed of plane a is 900 km/h
Plane b is moving at a rate of ![\dfrac{250\ km}{5\ h}=50\ km/h](https://tex.z-dn.net/?f=%5Cdfrac%7B250%5C%20km%7D%7B5%5C%20h%7D%3D50%5C%20km%2Fh)
It is required to find which plane is faster. To find which plane is faster, we need to compare their speeds.
Speed of a plane a is 900 km/h and that of plane b is 50 km/h. So, we can say that plane a is moving faster.
Answer:
4.25 J
Explanation:
Given that
mass of plastic ball = 11 g
Mass of plastic ball = 0.011 kg
velocity of ball = 29 m/s
We know that from work power energy theorem
![W_{all}=Change\ in\ kinetic\ energy\ of\ system](https://tex.z-dn.net/?f=W_%7Ball%7D%3DChange%5C%20in%5C%20kinetic%5C%20energy%5C%20of%5C%20system)
We know that kinetic energy of moving mass given as
![KE=\dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=KE%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
Now by pitting the values
![KE=\dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=KE%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
![KE=\dfrac{1}{2}\times 0.011\times 29^2](https://tex.z-dn.net/?f=KE%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%200.011%5Ctimes%2029%5E2)
KE= 4.25 J
So the work done on the ball is 4.25 J
<span>a) 1960 m
b) 960 m
Assumptions.
1. Ignore air resistance.
2. Gravity is 9.80 m/s^2
For the situation where the balloon was stationary, the equation for the distance the bottle fell is
d = 1/2 AT^2
d = 1/2 9.80 m/s^2 (20s)^2
d = 4.9 m/s^2 * 400 s^2
d = 4.9 * 400 m
d = 1960 m
For situation b, the equation is quite similar except we need to account for the initial velocity of the bottle. We can either assume that the acceleration for gravity is negative, or that the initial velocity is negative. We just need to make certain that the two effects (falling due to acceleration from gravity) and (climbing due to initial acceleration) counteract each other. So the formula becomes
d = 1/2 9.80 m/s^2 (20s)^2 - 50 m/s * T
d = 1/2 9.80 m/s^2 (20s)^2 - 50m/s *20s
d = 4.9 m/s^2 * 400 s^2 - 1000 m
d = 4.9 * 400 m - 1000 m
d = 1960 m - 1000 m
d = 960 m</span>
Power = work/time
P = 105J/103s
P = <span>1.019 watts</span>