1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ASHA 777 [7]
2 years ago
6

You have a lens whose focal length is –6.25 cm. You place an object on the axis of the lens at a distance of 10.7 cm from it. Ho

w far is the object\'s image from the lens (as a positive quantity)?
Physics
1 answer:
-BARSIC- [3]2 years ago
8 0

Answer:

3.95 cm

Explanation:

focal length of the lens, f = - 6.25 cm

distance of object from the lens, u = - 10.7 cm

Let the distance of image from the lens is v.

Use lens equation

\frac{1}{f}=\frac{1}{v}-\frac{1}{u}

\frac{1}{-6.25}=\frac{1}{v}+\frac{1}{10.7}

\frac{1}{-6.25}-\frac{1}{10.7}=\frac{1}{v}

\frac{1}{v}=\frac{-10.7-6.25}{66.875}

v = - 3.95 cm

Thus, the distance of image from the lens is 3.95 cm as the same side of object.

You might be interested in
A car of mass M = 1000 kg traveling at 50.0 km/hour enters a banked turn covered with ice. The road is banked at an angle θ , an
kupik [55]

The radius of the curved road at the given condition is 54.1 m.

The given parameters:

  • <em>mass of the car, m = 1000 kg</em>
  • <em>speed of the car, v = 50 km/h = 13.89 m/s</em>
  • <em>banking angle, θ = 20⁰</em>

The normal force on the car due to banking curve is calculated as follows;

Fcos(\theta) = mg

The horizontal force on the car due to the banking curve is calculated as follows;

Fsin(\theta) = \frac{mv^2}{r}

<em>Divide </em><em>the second equation by the first;</em>

\frac{Fsin(\theta)}{Fcos(\theta) } = \frac{mv^2}{rmg} \\\\tan(\theta) = \frac{v^2}{rg} \\\\r = \frac{v^2}{g \times tan(\theta)} \\\\r = \frac{13.89^2}{9.8 \times tan(20)} \\\\r = 54.1 \ m

Thus, the radius of the curved road at the given condition is 54.1 m.

Learn more about banking angle here: brainly.com/question/8169892

3 0
2 years ago
Example 7.3
marysya [2.9K]

Answer:

hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello

4 0
2 years ago
What is the acceleration of a body moving with uniform velocity?
AfilCa [17]

Acceleration is the rate of change of velocity, a body moving with uniform velocity does not possess acceleration at all i.e. acceleration is zero





3 0
3 years ago
A natural atom can be negatively charged by
svet-max [94.6K]

Answer:

By Gaining Electrons

Explanation:

A nuetral atom is negative when it gains electrons, and it can be positive when it loses electrons.

4 0
2 years ago
Read 2 more answers
a person throws a ball upward into the air with an initial velocity of 20 m/s. calculate (a) how high it goes, and (b) how long
Phantasy [73]

Answer:

a) about 20.4 meters high

b) about 4.08 seconds

Explanation:

Part a)

To find the maximum height the ball reaches under the action of gravity (g = 9.8 m/s^2) use the equation that connects change in velocity over time with acceleration.

a=\frac{Vf-Vi}{t}

-9.8 \frac{m}{s} =\frac{Vf-Vi}{t}

In our case, the initial velocity of the ball as it leaves the hands of the person is Vi = 20 m/s, while thw final velocity of the ball as it reaches its maximum height is zero (0) m/s. Therefore we can solve for the time it takes the ball to reach the top:

-9.8  =\frac{0-20}{t}\\t=\frac{20}{9.8} s = 2.04 s

Now we use this time in the expression for the distance covered (final position Xf minus initial position Xi) under acceleration:

Xf-Xi=Vi*t+\frac{1}{2} a t^{2} \\Xf-Xi=20*(2.04)-\frac{1}{2} 9.8*2.04^{2}\\Xf-Xi=20.408 m

Part b) Now we use the expression for distance covered under acceleration to find the time it takes for the ball to leave the person's hand and come back to it (notice that Xf-Xi in this case will be zero - same final and initial position)

Xf-Xi=0=20*(t)-\frac{1}{2} 9.8*t^{2

To solve for "t" in this quadratic equation, we can factor it out as shown:

0= t(20-\frac{9.8}{2} t)

Therefore there are two possible solutions when each of the two factors equals zero:

1) t= 0 (which is not representative of our case) , and

2) the expression in parenthesis is zero:

0= 20-\frac{9.8}{2} t\\t=\frac{20*2}{9.8} = 4.08 s

7 0
3 years ago
Other questions:
  • Which of these answers best describes a fossil?
    7·2 answers
  • Byron bought a keyless entry door lock that has the digits 0 through 9 on the keypad. He wants to choose a three-digit entry cod
    14·2 answers
  • Help!! I’ll give brainliest! Match the changes in sound wave properties with their effects on an observer.
    6·1 answer
  • If an atom had a nucleus 1 ft in diameter, what would be the diameter of the atom, in miles? (1 mi = 5,280 ft)
    7·1 answer
  • In the unsaturated zone, the pores of the soil are totally filled with water. T or F
    9·1 answer
  • Which SI units would you use for the following measurements?.
    14·1 answer
  • When a voltage difference is applied to a piece of metal wire, a 10.0 mA current flows through it. If this metal wire is now rep
    14·1 answer
  • LOADS OF POINTS - PLEASE SHOW WORKING AND METHOD USED
    12·2 answers
  • What two terms best describe the variable "air pressure inside the football" in this experiment?
    11·1 answer
  • What is the half of 3.24<br> Plzzz help me
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!