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Serjik [45]
2 years ago
5

What do u mean by free fall?​

Physics
1 answer:
Degger [83]2 years ago
7 0

Answer:

Any motion of a body in which gravity is the sole force acting on it is known as free fall. A body in free fall has no force acting on it under general relativity, where gravity is reduced to space-time curvature.

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<u>OAmalOHpeO</u>

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A  works to find magnitude. The leading negative sign gives us the positive magnitude after the correct velocity is found without it.

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3 years ago
Community psychologists are not<br> concerned with worker stress factors.<br> True<br> False
fgiga [73]
It would be false as your answer
8 0
2 years ago
A stone is thrown up from the top of a tower. It reaches the ground in 5.64 seconds. A second stone is thrown down from the same
Naddik [55]

Answer:

add 5.64 to 3.6 where you'll find your awnser

Explanation:

8 0
3 years ago
A dog runs 3 miles and 4 miles west in 6 hours. What’s the dogs total distance and displacement ?
Inga [223]

Complete question:

A dog runs 3 miles east and 4 miles west in 6 hours. What’s the dogs total distance and displacement ?

Answer:

The total distance covered by the dog is  7 miles

The displacement of the dog is 1 mile west

Explanation:

Given;

initial position of the dog = 3 miles east

final position of the dog = 4 miles west

time of motion, t = 6 hours

The total distance covered by the dog is given as;

Total distance = 3 miles + 4 miles = 7 miles

The displacement of the dog is given as;

displacement = final position of the dog  - initial position of the dog

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6 0
3 years ago
A metal sphere of radius 10 cm carries a charge of 2.0 MicroCoulomb.What is the magnitude of the electric field 5.0 cm from the
nekit [7.7K]

Answer:

E = 7200 J = 7.2 KJ

Explanation:

The electric field due to a sphere is similar to the electric field due to a point charge. It is calculated by the use of the following formula:

E = \frac{kq}{r^2}\\

where,

E = Electric Field = ?

k = Coulomb Constant = 9 x 10⁹ Nm²/C²

q = charge on sphere = 2 μC = 2 x 10⁻⁶ C

r = distance from the center of the sphere to the location = 5 cm = 0.05 m

Therefore,

E = \frac{(9\ x\ 10^9\ Nm^2/C^2)(2\ x\ 10^{-6}\ C)}{(0.05\ m)^2}

<u>E = 7200 J = 7.2 KJ</u>

6 0
3 years ago
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