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3 years ago

11

Which is a possible disadvantage of using flowing water to produce electricity?

1 answer:

Anastasy [175]3 years ago

3 0

<span>Drought
....................</span>

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You are given a copper bar of dimensions 3 cm × 5 cm × 8 cm and asked to attach leads to it in order to make a resistor. (a) If

dem82 [27]

Answer:

A) If you want to achieve the SMALLEST possible resistance, you should attach the leads to the opposite faces that measure b) 5 cm by 8 cm.

B) If you want to achieve the LARGEST possible resistance, you should attach the leads to the opposite faces that measure a) 3 cm × 5 cm

Explanation:

Resistivity is directly proportional to lenght and inversely properly to cross sectional area.

For the first case, 5 cm by 8 cm gives the largest area and leave 3 cm as the lenght. The resistivity of the metal will be smallest in these dimensions.

For the second case, 3 cm by 5 cm gives the smallest area, leaving 8 cm as the lenght. This is the maximum arrangement that can give the largest resistance possible.

4 0

3 years ago

How many times higher could an astronaut jump on the Moon than on Earth if his takeoff speed is the same in both locations (grav

JulsSmile [24]

Answer:

maximum height on moon is 6 times more than the maximum height on Earth

Explanation:

Let the Astronaut has its maximum speed by which he can jump is "v"

now for the maximum height that it can jump is given as

$v_f^2 - v_i^2 = 2 aH$

now from above equation we will have

$0 - v^2 = 2(-g)H$

now we have

$H = \frac{v^2}{2g}$

now if Astronaut jump on the surface of moon with same speed

then we know that the acceleration of gravity on surface of moon is 1/6 times the gravity on earth

so at surface of moon we have

$0 - v^2 = 2(-g/6) H$

now we have

$H = \frac{6v^2}{2g}$

so maximum height on moon is 6 times more than the maximum height on Earth

8 0

3 years ago

Is a electron a positively charged, negatively charged, or a neutral particle

Effectus [21]

An electron is negatively charged.

3 0

3 years ago

a uniform rod is hung at onen end and is partially submerged in water. If the density of the rod is 5/9 than of wter, find the f

34kurt

Answer:

$\frac{h_{liquid} }{ h_{body} }$ = 5/9

Explanation:

This is an exercise that we can solve using Archimedes' principle which states that the thrust is equal to the weight of the desalted liquid.

B = ρ_liquid g V_liquid

let's write the translational equilibrium condition

B - W = 0

let's use the definition of density

ρ_body = m / V_body

m = ρ_body V_body

W = ρ_body V_body g

we substitute

ρ_liquid g V_liquid = ρ_body g V_body

$\frac{\rho_{body} }{\rho_{liquid} } } = \frac{V_{liquid} }{V_{body} } }$

In the problem they indicate that the ratio of densities is 5/9, we write the volume of the bar

V = A h_bogy

Thus

$\frac{V_{liquid} }{V_{1body} } = \frac{ h_{liquid} }{h_{body} }$

we substitute

5/9 = $\frac{h_{liquid} }{ h_{body} }$

8 0

2 years ago

The rocket now has a thruster that malfunctions and is now pushing the rocket in the wrong direction. What is the new net force

Lana71 [14]

Answer:

Daddy Dr Dr Dr Dr

Explanation:

3 0

3 years ago

Read 2 more answers