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Semmy [17]
3 years ago
11

If our year were twice as long (that is, if Earth took twice as many days to complete each orbit around the Sun), but Earth's ro

tation period and axis tilt were unchanged, then ____
Physics
1 answer:
Flauer [41]3 years ago
6 0

Answer:

the four seasons would each be twice as long as they are now

Explanation:

A year is the result of the Earths revolution around the sun i.e., the Earth takes 365 days to complete one revolution around the sun. A day is the result of the Earth's rotation on its axis i.e., it takes 24 hours for Earth to complete one rotation on its axis.

The Earth is titled by about 23.5 degrees, this results in the seasons of Earth. The distance from the sun has nothing to do with the seasons. During the northern hemisphere winter the Earth is actually closer to the sun than in the summer. So, if our year was twice as long then the seasons would be twice as long.

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What is a variable that gives location relative to an origin?
AysviL [449]
The variable would be “X”
4 0
3 years ago
Read 2 more answers
You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi
Mama L [17]

Answer:

Explanation:

Given that, .

The half-life of a radioactive element is

t½ = 1 hr.

At the first hour, the radioactive element has 40 counts/minute

After 4 hours it has 5 counts/minute

So,

We want to filled the table.

0 hours, I.e at the start

40 counts/mins × 2 = 80 counts / mis

First half-life (first hour) is

40 counts/mins

Second half-life (second hour)

40 counts/mins × ½ = 20 counts/mins

Third half-life (third hour)

40 counts/mins × ¼ = 10 counts / mins

Fourth half life (fourth hour)

40 counts/mins × ⅛ = 5 counts / mins

So, the table is

Time........................Geiger Counter Rate

0 hours.................... 80 counts / minutes

1 hour........................ 40 counts / minutes

2 hours..................... 20 counts / minutes

3 hours..................... 10counts / minutes

4 hours...................... 5 counts / minute

6 0
3 years ago
How did you know if an electric current is<br> flowing in a lightbulb?
sweet [91]

Answer:

if it lights up

Explanation:

electricity

7 0
3 years ago
Light with a wavelength of 400 nm strikes the surface of cesium in a photocell, and the maximum kinetic energy of the electrons
Firdavs [7]

Answer:

The longest wavelength of light that is capable of ejecting electrons from that metal is 1292 nm.

Explanation:

Given that,

Wavelength = 400 nm

Energy E=1.54\times10^{-19}\ J

We need to calculate the longest wavelength of light that is capable of ejecting electrons from that metal

Using formula of energy

E = \dfrac{hc}{\lambda}

\lambda=\dfrac{hc}{E}

Put the value into the formula

\lambda=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{1.54\times10^{-19}}

\lambda=1292\times10^{-9}\ m

\lambda=1292\ nm

Hence, The longest wavelength of light that is capable of ejecting electrons from that metal is 1292 nm.

8 0
3 years ago
The speed of a boat in still water is 20 mph. it travels from one pier to another with the current in 4 hours and back against t
saw5 [17]
The answer is, "the speed of the current is 5 miles per hour."

To calculate the speed of the current,
let's assume speed of current =  xmph. Time taken to travel from one pier to another with the current = 100/(20+x)h


But the time taken to travel from one pier to another with the current, which is given is = 4 hours. So,  4=100/(20+x) 80+4x = 100

4x = 20

x = 5 Thus, the speed of the current is 5 miles per hour.
3 0
3 years ago
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