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Semmy [17]
3 years ago
11

If our year were twice as long (that is, if Earth took twice as many days to complete each orbit around the Sun), but Earth's ro

tation period and axis tilt were unchanged, then ____
Physics
1 answer:
Flauer [41]3 years ago
6 0

Answer:

the four seasons would each be twice as long as they are now

Explanation:

A year is the result of the Earths revolution around the sun i.e., the Earth takes 365 days to complete one revolution around the sun. A day is the result of the Earth's rotation on its axis i.e., it takes 24 hours for Earth to complete one rotation on its axis.

The Earth is titled by about 23.5 degrees, this results in the seasons of Earth. The distance from the sun has nothing to do with the seasons. During the northern hemisphere winter the Earth is actually closer to the sun than in the summer. So, if our year was twice as long then the seasons would be twice as long.

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Explain how the situation shown above would be different if the skier experiences friction while traveling downhill. Include the
aleksandrvk [35]

Answer:

The force of friction acts in the direction opposite to the direction of motion. If friction would have been applied to the skier it would have resulted in a lower velocity and less kinetic energy.

Explanation:

5 0
3 years ago
A brick falls to the ground. if the time for the collision of the brick and the ground is increased by a factor of 4, the force
melomori [17]

Answer:

By a factor of 1/4.

Explanation:

The impulse force that applies to an object undergoing rapid deceleration just before coming to a stop on the ground is given by the following formula,

\\\begin{aligned}\\\small F &=\small \frac{\Delta (mV)}{\Delta T}\end{aligned}

in which \small \Delta (mV) , \small \Delta t represent the change in momentum and the time taken for that change.

If one increases the time that is taken for the momentum change (which remains constant for this situation) by a factor 4 and if that new force is represented by \small F_1, the following manipulation confirms the answer to this question.

\begin{aligned}\\\small F_1 &=\small \frac{\Delta (mV)}{4\Delta t}\\\\&=\small \frac{1}{4}\times\bigg[\frac{\Delta (mV)}{\Delta t}\bigg]\\\\&=\small \frac{1}{4}F\end{aligned}

Here \small F is the force that was applied to the object previously.

#SPJ4

4 0
2 years ago
- What do the objects not in motion have in common?​
Semenov [28]

Answer:

they have zero velocity

Explanation:

8 0
3 years ago
True or false: Only people that hold opinions of the group should get to express their opinion.
PilotLPTM [1.2K]

Answer:

true

Explanation:

this is fair to other people

5 0
3 years ago
The weight of an object _____.
denis23 [38]

The weight of an object is the force with which it is attracted to earth. The gravity of an object or body of an object is high on earth than at the atmosphere. It has an average of gravitational constant equal to 9.8066 or 9.8 meters per second. In truth, the acceleration of the object depend upon its location, the latitude and altitude, on earth.     

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8 0
3 years ago
Read 2 more answers
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