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Olegator [25]
3 years ago
10

A large container is pulled 20 meters with 40 newtons of force. The power exerted is 64 watts. How long did it take to move the

container?
A. 12.5 s
B. 40 s
C. 125 s
D. 250 s
Physics
1 answer:
Usimov [2.4K]3 years ago
3 0
A.(20*40)/64=12.5 hope i helped
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PE=30J, m=?, g=10m/s2, h=10m
OleMash [197]
Based on the given, this is probably a gravitational potential energy problem (PEgrav). The formula for PEgrav is:

PEgrav = mgh

Where:
m = mass (kg)
g = acceleration due to gravity
h = height (m)

With this formula you can derive the formula for your unknown, which is mass. First put in what you know and then solve for what you do not know.

PEgrav=mgh
30J=m(10)(10[tex] \frac{30}{100} =m)[/tex]

Do operations that you can with what is given first.

30J=m(100m)

Transpose the 100 to the other side of the equation. Do not forget that when you transpose, you do the opposite operation.

\frac{30}{100} =m

m = 0.30kg

5 0
2 years ago
suppose that you want to build a machine to perform simple tasks. why must you understand all about forces to complete your miss
mixas84 [53]

Answer:

CAUSE YPU WANT TO

Explanation:

4 0
2 years ago
A 30 kg TV falls out of a 5 meter high window, reaching a
butalik [34]

Answer:

300kgm/s

Explanation:

Given parameters:

Mass of TV = 30kg

Height of building  = 5m

Maximum speed  = 10m/s

Unknown:

Momentum before it hits the ground = ?

Solution:

Momentum is the quantity of motion a body possess or contains. It is expressed as;

      Momentum  = mass x velocity

 Insert the parameters and solve;

   Momentum  = 30 x 10

   Momentum  = 300kgm/s

8 0
2 years ago
Read 2 more answers
Question 2 of 10
mamaluj [8]

Answer:

2.00 A

Explanation:

Total resistance = 10 + 20 + 30 = 60 ohms

Potential difference (V) = 120volts

Current (I) =?

from Ohms law V = IR

==> I = V/R = 120/60 = 2 A

Note: for resistors in series equal amount of electric current flows through the circuit

7 0
2 years ago
What is the least value of an ammeter <br>Is it 1. 0.1<br>2. 0.10<br>3. 0.2<br>4. 0.5​
givi [52]

The least value varies depends on ammeter range. In the given question, ammeter range is not mentioned. So, the least value of an ammeter is 0.1 or 0.5 (depends on ammeter range).

<u>Explanation:</u>

The least value of an ammeter is the measure of the smallest number which can be observed in ammeter. So the least value will be varying depending upon its range. If we consider the range of ammeter is 30 A and the scale readings are 10 numbers, then the least value will be 30/10 = 3 A per scale.

So the least value is determined as \frac{Range of ammeter}{No.of scales}

So among the given options 0.1 is most suitable for an ammeter with range of 3 A with 30 divisions.

3 0
2 years ago
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