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Olegator [25]
3 years ago
10

A large container is pulled 20 meters with 40 newtons of force. The power exerted is 64 watts. How long did it take to move the

container?
A. 12.5 s
B. 40 s
C. 125 s
D. 250 s
Physics
1 answer:
Usimov [2.4K]3 years ago
3 0
A.(20*40)/64=12.5 hope i helped
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A factory worker pushes a crate of mass 31.0 kg a distance of 4.35 m along a level floor at constant velocity by pushing horizon
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a. 79.1 N

b. 344 J

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a. Since the crate has a constant velocity, its net force must be 0 according to Newton's 1st law. The push force F_p by the worker must be equal to the friction force F_f on the crate, which is the product of friction coefficient μ and normal force N:

Let g = 9.81 m/s2

F_p = F_f = \mu N = \mu mg = 0.26 * 31 * 9.81 = 79.1 N

b. The work is done on the crate by this force is the product of its force F_p and the distance traveled s = 4.35

W_p = F_ps = 79.1*4.35 = 344 J

c. The work is done on the crate by friction force is also the product of friction force and the distance traveled s = 4.35

W_f = F_fs = -79.1*4.35 = -344 J

This work is negative because the friction vector is in the opposite direction with the distance vector

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