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velikii [3]
3 years ago
5

"In a Young’s double-slit experiment, the separation between slits is d and the screen is a distance D from the slits. D is much

greater than d and λ is the wavelength of the light. The number of bright fringes per unit width on the screen is: "
A. Dd/λ
B. Dλ/d
C. D/dλ
D. λ/Dd
E. d/Dλ"
Physics
1 answer:
san4es73 [151]3 years ago
6 0

Answer:

The number of bright fringes per unit width on the screen is, x=\dfrac{\lambda D}{d}      

Explanation:

If d is the separation between slits, D is the distance between the slit and the screen and \lambda is the wavelength of the light. Let x is the  number of bright fringes per unit width on the screen is given by :

x=\dfrac{n\lambda D}{d}

\lambda is the wavelength

n is the order

If n = 1,

x=\dfrac{\lambda D}{d}

So, the the number of bright fringes per unit width on the screen is \dfrac{\lambda D}{d}. Hence, the correct option is (B).

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