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mart [117]
3 years ago
5

help please According to the Universal Law of Gravitation, every object attracts every other object in the universe. Why can’t y

ou feel the force of attraction between you and Mars?
Physics
1 answer:
mel-nik [20]3 years ago
6 0
Cause of earth’s gravitational pull is stronger then Mars
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Which part of the electromagnetic spectrum is nearest to radio waves?
svetlana [45]

The part of the electromagnetic spectrum closest to radio waves is <u> microwaves</u>.

The wavelength of radio waves ranges from 10 cm to more than 1 km. The part of the electromagnetic spectrum that occurs closest to the radio waves is called the microwave region.

Microwaves have wavelengths ranging from around 1 mm to 10 cm.

The waves overlap in the region of 10 cm.

Thus, the region of electromagnetic spectrum closest to radiowaves is <u> microwaves.</u>

3 0
3 years ago
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The flash unit in a camera uses a special circuit to "step up" the 3.0 V from the batteries to 290 V, which charges a capacitor.
Margaret [11]

Answer:

Therefore the capacitance of the capacitor is 2.38 * 10⁻⁵F

Explanation:

We apply the concepts related to Power and energy stored in a capacitor.

By definition we know that power is represented as

P = \frac{E}{t}

Where,

E= Energy

t = time

to find the Energy we have,

E = P*t

P = 1*10^5Wt = 10*10^{-6}s

E= (1*10^5)(10*10^{-6})E = 1.0J

With the energy found we can know calculate the Capacitance in a capacitor through the energy for capacitor equation, that is

E=\frac{1}{2}CV^2

C = \frac{2E}{V^2}\\\\\\\frac{2\times 1 }{290^2 - 3^2\\} \\= 2.38 \times 10^-^5F

Therefore the capacitance of the capacitor is 2.38 * 10⁻⁵F

3 0
3 years ago
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Solved, just need someone to check! thank you. ​
Lady bird [3.3K]

Answer:

good job keep it up

Explanation:

3 0
3 years ago
A circuit contains a 6.0-v battery, a 4.0-w resistor, a 0.60-µf capacitor, an ammeter, and a switch all in series. what will be
77julia77 [94]
<span>You are given a circuit that contains a 6.0-v battery, a 4.0 ohm resistor, a 0.60 micro farad capacitor, an ammeter, and a switch all in series. You are asked to find the current reading after the switch is closed. Apply ohms law where V = IR where V is the voltage, I is the current and R is the resistor.</span>

V = IR
I = V/R
I = 6 volts / 4 ohms
I = 1.5A

When the switch is closed, the cathode side plate begins to fill up with electrons when it was originally empty before the switch was closed. When it fills up the cathode side of the circuit, the current decreases. And when the capacitor cannot hold more electrons, the current will stop. The higher the capacitance, the higher is the capacity to store electrons.
4 0
3 years ago
Read 2 more answers
A motobike's tire rotates with a constant angular speed of 62.8 rad/s. The radius of a tire is 30cm. Assuming that no slipping o
Dmitriy789 [7]

Answer:

12.6 m/s

Explanation:

We know that the linear speed v = rω where r = radius and ω = angular acceleration. Given that ω = 62.8 rad/s and r = 20 cm from center = 0.2 cm

So, v = rω

= 0.2 m × 62.8 rad/s

= 12.56 m/s

≅12.6 m/s

7 0
3 years ago
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