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3 years ago

5

help please According to the Universal Law of Gravitation, every object attracts every other object in the universe. Why can’t y

ou feel the force of attraction between you and Mars?

1 answer:

mel-nik [20]3 years ago

6 0

Cause of earth’s gravitational pull is stronger then Mars

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Licemer1 [7]

By V=IR
A: 24=I*20
I = 1.2A

B: 220 = I*250
I = 0.88A

C: 6= I*3
I = 2 A

C,A,B

3 0

3 years ago

Read 2 more answers

25 POINTS ------------------ (usatestprep)

Airida [17]

Answer:

D) The heavier ball will have a higher temperature because the change of temperature is inversely proportional to mass.

Explanation:

As stated in the problem, the amount of heat released by each ball is

$Q=mC_p \Delta T$

where

m is the mass of the ball

Cp is the specific heat of iron (so, it is equal for both balls)

$\Delta T$ is the change in temperature of each ball

In this problem, we are said that the amount of heat released by the two balls, Q, is the same. Cp is also the same: this means that the product $m\Delta T$ must be the same for the two balls. So, the mass and the change in temperature are inversely proportional: therefore, the heavier ball will have a smaller change in temperature. And since both balls starts from the same temperature, 100 C, this means that the heavier ball will reach a higher temperature than the lighter ball.

6 0

3 years ago

The element chlorine is found in nature as a molecule that can be represented as - A. Cl.

poizon [28]

A
Cl is the chemical symbol for chlorine numbers after it are isotopes

5 0

3 years ago

Susan, driving north at 53 mphmph , and Shawn, driving east at 63 mphmph , are approaching an intersection. Part A What is Shawn

mafiozo [28]

Answer:

Shawn's speed relative to Susan's speed = 10 mph

Resultant velocity = 82.32 mph

Explanation:

The given data :-

i) Susan driving in north and speed of Susan is ( v₁ ) = 53 mph.

ii) Shawn driving in east and speed of Shawn is ( v₂ ) = 63 mph.

iii) The speed of both Susan and Shawn is relative to earth.

iv) The angle between Susan in north and Shawn in east is 90°.

We have to find Shawn's speed relative to Susan's speed.

v₂₁ = v₂ - v₁ = 63 - 53 = 10 mph

Resultant velocity,

$v = \sqrt{v_{2} ^{2}+ v_{1} ^{2} } =\sqrt{63^{2} +53^{2} }$

v = 82.32 mph

5 0

3 years ago

A piano tuner sounds two strings simultaneously. One has been previously tuned to vibrate at 293.0 Hz. The tuner hears 3.0 beats

ololo11 [35]

Answer:

Part a)

$f_B = 290 Hz$

Part B)

percentage increase is

$percentage = 1.38$ %

Explanation:

Part a)

As we know that the beat frequency is

$f_A - f_B = 3$

after increasing the tension the beat frequency is decreased and hence the tension in string B will increase

So we have

$293 - f_B = 3$

$f_B = 290 Hz$

Part B)

percentage increase in the tension of the string will be given as

$f_A - f_B' = 1$

$f_B' = 292 Hz$

now we have

$f = \frac{1}{2L}\sqrt{\frac{T}{\mu}}$

so we have

$T_1 = C (290)^2$

$T_2 = C(292)^2$

so we have

$\frac{\Delta T}{T} = \frac{292^2 - 290^2}{290^2}$

percentage increase is

$percentage = 1.38$

4 0

3 years ago