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jekas [21]
4 years ago
12

Question 14 (5 points)

Chemistry
1 answer:
Svetach [21]4 years ago
5 0

Answer:

D) 2.01 x 10⁻⁴ .

Explanation:

pH = 2.11

[ H⁺ ] = 10^{-2.11}  

Let the acid be HA

It will ionise as follows .

                                        HA       ⇄       H⁺       +        A⁻

in equilibrium                 .30               10^{-2.11}          10^{-2.11}         

Acid ionisation constant Ka  =   \frac{(10^{-2.11})^2}{0.3}

= 2 x 10⁻⁴                

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Sodium acetate can be formed from the metathesis/double replacement reaction of sodium
telo118 [61]

Answer:

Explanation:

Sodium Acetate Trihydrate BP Specifications

Sodium Acetate BP

C2H3NaO2,3H2O

Action and use

Used in solutions for dialysis; excipient.

DEFINITION

Sodium ethanoate trihydrate.

Content

99.0 per cent to 101.0 per cent (dried substance).

CHARACTERS

Appearance

Colourless crystals.

Solubility

Very soluble in water, soluble in ethanol (96 per cent).

IDENTIFICATION

A. 1 ml of solution S (see Tests) gives reaction (b) of acetates.

B. 1 ml of solution S gives reaction (a) of sodium.

C. Loss on drying (As shown in the Relevant Test).

TESTS

Solution S

Dissolve 10.0 g in carbon dioxide-free water prepared from distilled water R and dilute to 100 ml 100 ml with the same solvent.

Appearance of solution

Solution S is clear and colourless.

pH

7.5 to 9.0.

Dilute 5 ml of solution S to 10 ml with carbon dioxide-free water.

Reducing substances

Dissolve 5.0 g in 50 ml of water, then add 5 ml of dilute sulphuric acid and 0.5 ml of 0.002 M potassium permanganate. The pink colour persists for at least 1 h. Prepare a blank in the same manner but without the substance to be examined.

Chlorides

Maximum 200 ppm.

Sulphates

Maximum 200 ppm.

Aluminium

Maximum 0.2 ppm, if intended for use in the manufacture of dialysis solutions.

Arsenic

Maximum 2 ppm, determined on 0.5 g.

Calcium and magnesium

Maximum 50 ppm, calculated as Ca.

Heavy metals

Maximum 10 ppm.

Iron

Maximum 10 ppm, determined on 10 ml of solution S.

Loss on drying

39.0 per cent to 40.5 per cent, determined on 1.000 g by drying in an oven at 130C.

Sodium Acetate FCC Food Grade, US Food Chemical Codex

C2H3NaO2 Formula wt, anhydrous 82.03

C2H3NaO2·3H2O Formula wt, trihydrate 136.08

DESCRIPTION

Sodium Acetate occurs as colorless, transparent crystals or as a granular, crystalline or white powder. The anhydrous form is hygroscopic; the trihydrate effloresces in warm, dry air. One gram of the anhydrous form dissolves in about 2 mL of water; 1 g of the trihydrate dissolves in about 0.8 mL of water and in about 19 mL of alcohol.

Function: Buffer.

REQUIREMENTS

Identification: A 1:20 aqueous solution gives positive tests for Sodium and for Acetate.

Assay: Not less than 99.0% and not more than 101.0% of C2H3NaO2 after drying.

Alkalinity Anhydrous: Not more than 0.2%; Trihydrate: Not more than 0.05%.

Lead: Not more than 2 mg/kg.

Loss on Drying: Anhydrous: Not more than 1.0%; Trihydrate: Between 36.0% and 41.0%.

Potassium Compounds: Passes test.

5 0
3 years ago
Necesito la respuesta
aleksandrvk [35]

Answer:

la tercera caja (3rd box)

Explanation:

usa desmos para obtener más ayuda

4 0
3 years ago
What is the major underlying principle of chromatography?.
KatRina [158]
Separation will be achieved if one component adheres to the stationary phase more than the other component does.
6 0
2 years ago
Read 2 more answers
what would happen if we lost our planets core on earth blew up, would we all die or will we lose gravity or suficate, pls help.
sergeinik [125]

Answer: if we lost our core it would be an entire fallout like fallout 76 we would have no way to protect ourselves from the radiation of space except for a select few that actually own astronaut suits tho we would not turn into monsters, sadly :( I wanna be a ghoul

3 0
2 years ago
Separation technique used to separate mud and water without heating​
Murrr4er [49]

Answer:

Separation technique used to separate mud and water without heating​:

<u>Sedimentation-Decantation</u>

<u></u>

Explanation:

<em>1.The settling of the heavier particle at the bottom when the container is left undisturbed is called </em><u><em>sedimentation.</em></u>

<u><em></em></u>

<u><em>In a mixture of Mud and water :</em></u>

In this process the heavy mud particles settle at the bottom due to their high density .

2. Decantation : It is the process of pouring out the upper clear layer of the light particles.

<u><em>In a mixture of Mud and water :</em></u>

The water is lighter and form a clear layer over the settled mud particles. Hence by decantation the clear water is poured into a clean separate container

Thus mud remain in the bottom and the mixture is separated

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