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Tpy6a [65]
3 years ago
13

Weak acids:

Chemistry
1 answer:
zloy xaker [14]3 years ago
4 0
Weak acids only partially ionize. so the retain part of the original molecule. C
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How many moles of oxygen gas are needed to react completely with 17.9 mL Mg, with a density of 1.74 g/mL?
Rom4ik [11]
For the answer to the question above, <span>17.9 x 1.74 gram Mg = 31.15 gram Mg = (31.15/24.31) = 1.28 mole Mg </span>

<span>2 Mg + O2 ---> 2MgO </span>

<span>so 1.28 mole Mg reacts with 0.641 mole O2

I hope my answer helped you. Feel free to ask more questions. Have a nice day!</span>
6 0
3 years ago
Read 2 more answers
5.60g of glyceraldehydes was dissolved in 10ml of a solvent and placed in a 50mm cell if the rotation is 1.74 calculate the spec
KonstantinChe [14]

Answer:

6.214 degrees-mL/gdm

Explanation:

The specific rotation α' = α/LC where α = observed rotation, L = length of tube and C = concentration of solution.

Given that α = 1.74, L = length of cell = 50 mm = 0.50 dm and C = m/V where m = mass of glyceraldehyde = 5.60 g and V = volume = 10 ml

So, C = m/V = 5.60 g/10 ml = 0.560 g/ml

Since α' = α/LC

substituting the values of the variables into the equation, we have

α' = α/LC

α' = 1.74/(0.50 dm × 0.560 g/ml)

α' = 1.74/(0.28 gdm/l)

α' = 0.006214 °mL/gdm

α' = 6.214 °mL/gdm

α' = 6.214 degrees-mL/gdm

7 0
3 years ago
A jet airplane has a velocity of 1145 knots. A knot is 1 nautical mile (nm)/hr. A nautical
ra1l [238]

Answer:

589.038 m/s

Explanation:

i dont know if did this right tho

4 0
2 years ago
At 500°C the equilibrium constant, Kp, is 4.00 × 10–4 for the equilibrium: 2HCN(g) H2(g) + C2N2(g) What is Kp for the following
Andrews [41]

<u>Answer:</u> The value of K_p for the equation is 2.5\times 10^3

<u>Explanation:</u>

The given chemical reaction is:

2HCN(g)\rightleftharpoons H_2(g)+C_2N_2(g);K_1

The chemical equation for which the equilibrium constant is to be calculated follows:

H_2(g)+C_2N_2(g)\rightleftharpoons 2HCN(g);K_p

As, the equation is the result of the reverse of given reaction. So, the equilibrium constant for the equation will be the inverse of equilibrium constant for the given reaction.

The value of equilibrium constant for the equation is:

K_p=\frac{1}{K_1}

We are given:

K_1=4.00\times 10^{-4}

Putting values in above equation, we get:

K_p=\frac{1}{4.00\times 10^{-4}}=2.5\times 10^3

Hence, the value of K_p for the equation is 2.5\times 10^3

3 0
4 years ago
Helpppppp please please
polet [3.4K]
What do we do? hehehehe
6 0
3 years ago
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