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ICE Princess25 [194]
4 years ago
6

Balance the equation

0_%7B3%7D%20" id="TexFormula1" title="O_{2}+ Fe --\ \textgreater \ Fe _{2} O _{3} " alt="O_{2}+ Fe --\ \textgreater \ Fe _{2} O _{3} " align="absmiddle" class="latex-formula">
Chemistry
1 answer:
Setler [38]4 years ago
7 0
Balanced chemical equation:


3 O2 + 4 Fe = 2 Fe2O3

hope this helps!.

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Might set a fire if you keep it plugged in or the fan could cut someone
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4 years ago
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A gas is contained in a tick walled balloon. When the pressure changes from 2. 95atm to ___atm, the volume changes from 7. 456L
tia_tia [17]

A gas is contained in a tick-walled balloon. When the pressure changes from 2. 95atm to <u>2.57</u> atm. p.

<h3>What is pressure?</h3>

Pressure is a force perpendicular to the unit area on which it is applied.

Given that, P1, the initial pressure is 2.95 atm

The initial volume, V1 = 7.456 L

The final volume, V2 = 4.782 L

The initial temperature, T1 =  379k

The final temperature, T2 = 212k

The equation will be

\dfrac{P_1V_1}{T_1 } =\dfrac{P_2V_2}{T_2}

Putting the values in the equation

\dfrac{2.95 \times 7.456 L }{379k } =\dfrac{P_2\times 4.782 L}{212k}\\\\\\P_2 = \dfrac{2.95 \times 7.456 L \times 212k }{379k \times 4.782 L} = 2.57\;atm.

Thus, the pressure changes from 2. 95atm to <u>2.57</u> atm p.

Learn more about pressure

brainly.com/question/12971272

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7 0
3 years ago
Calculate the mass of 6.9 moles of nitrous acid (HNO2). Explain the process or show your work by including all values used to de
AlexFokin [52]

Answer:- 324.3 grams.

Solution:-  We have been given with 6.0 moles of nitrous acid and asked to calculate it's grams. Moles to grams is a unit conversion and for doing this conversion we multiply the given moles by the molar mass of the compound.

Molar mass is the formula mass and to calculate this the atomic masses of each atom are multiplied by their respective subscripts that is the number of the atom in the compound .

For example, NO_2 has one nitrogen atom and one oxygen atom. So, the molar mass of this is = atomic mass of N + 2(atomic mass of O)

= 14 + 2(16)

= 14 + 32  

= 46 gram per mol

gram per mol is the unit of molar mass. So, the molar mass of NO_2 is 46 grams per mol.

Let's calculate the molar mass of nitrous acid using the same concept.

molar mass of [HNO_2 = 1 + 14 + 2(16)

= 1 + 14 + 32

= 47 grams per mol

Now, 6.9 moles of nitrous acid could easily be converted to grams as:

6.9molHNO_2(\frac{47g}{1mol})

= 324.3 g

Hence, the mass of 6.9 moles of nitrous acid is 324.3 grams.

6 0
3 years ago
Please help fast...please
RSB [31]

Answer:

Radioactive

Explanation:

hope this helped! :)

5 0
4 years ago
Gaseous compound Q contains only xenon and oxygen. When 0.100 gg of Q is placed in a 50.0 mLmL steel vessel at 0 ∘C∘C, the press
asambeis [7]

The question is incomplete, here is the complete question:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0°C, the pressure is 0.229 atm. What is the likely formula of the compound?

A. XeO

B. XeO_4

C. Xe_2O_2  

D. Xe_2O_3

E. Xe_3O_2

<u>Answer:</u> The chemical formula of the compound is XeO_4

<u>Explanation:</u>

To calculate the molecular mass of the compound, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{w}{M}RT

where,

P = Pressure of the gas = 0.229 atm

V = Volume of the gas  = 50.0 mL = 0.050 L     (Conversion factor:  1 L = 1000 mL)

w = Weight of the gas = 0.100 g

M = Molar mass of gas  = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gas = 0^oC=273K

Putting value in above equation, we get:

0.229\times 0.050=\frac{0.100}{M}\times 0.0821\times 273\\\\M=\frac{0.100\times 0.0821\times 273}{0.229\times 0.050}=195.4g/mol\approx 195g/mol

The compound having mass as 195 g/mol is XeO_4

Hence, the chemical formula of the compound is XeO_4

5 0
3 years ago
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