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Murrr4er [49]
3 years ago
5

If a system has cind independent components, what is the maximum number of phases that can exist in equilibrium? (b) A given sys

tem has eight liquid phases in equilibrium with each other. What must be true about the number of independent components in this system?
Chemistry
1 answer:
stellarik [79]3 years ago
7 0

Answer:

a) the maximum number of phases that can exist in equilibrium is c_{ind + 2

b) the number of independent components in this system are 6

Explanation:

We know that, The degree of freedom f for a system can be simply referred to as number of variables that must be defined to completely solve a system.

If degree of freedom is 0, then any problem is can be solved.

a) If a system has cind independent components, what is the maximum number of phases that can exist in equilibrium?

The degree of freedom for a system can be written as;

f = c_{ind - p + 2

where f is the degree of freedom

c_{ind is the number of independent component

so we solve for c_{ind

c_{ind = f + p - 2

we know that f can not be less than 0

Hence maximum possible face will be;

c_{ind = p - 2

p = c_{ind + 2

Therefore, the maximum number of phases that can exist in equilibrium is c_{ind + 2

b) A given system has eight liquid phases in equilibrium with each other. What must be true about the number of independent components in this system?

Number of phases in the system p = 8

p = c_{ind + 2

c_{ind = p - 2

we substitute

c_{ind = 8 - 2

c_{ind = 6

Therefore, the number of independent components in this system are 6

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Answer:

The answer to your question is given below

Explanation:

To convert from Particles to grams, one must have a clear understanding of Avogadro's hypothesis. From the Avogadro's hypothesis, we can easily convert from mole to particles and to grams.

Avogadro's hypothesis gives us a background understanding that 1 mole of any substance contains 6.02x10^23 particles. With this in mind we can easily convert particles to grams and grams to particles.

Now consider the following example:

1. How many particles are there in 4g of carbon?

Solution:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 particles. This implies that 1 mole of carbon contains 6.02x10^23 particles.

1 mole of carbon = 12g

Now we can say that 12g of carbon contains 6.02x10^23 particles.

If 12g of carbon contains 6.02x10^23 particles,

then 4g of carbon will contain = (4x6.02x10^23) /12 = 2.01x10^23 particles.

The next example will teach us how to convert from particles to grams..

2. What mass of helium contains 4.2x10^24 particles.

Solution:

According to Avogadro's hypothesis,

1 mole of He contains 6.02x10^23 particles.

1 mole of He = 4g

We can thus, say that 4g of He contains 6.02x10^23 particles.

1f 4g of He contains 6.02x10^23 particles,

Then Xg of He contains 4.2x10^24 Particles i.e

Xg of He = (4x4.2x10^24)/(6.02x10^23)

Xg of He = 27.91g

Therefore, 27.91g of He contains 4.2x10^24 Particles

With the above illustrations I believe you have understood how to convert from grams to particles and from particles to grams.

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