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Murrr4er [49]
2 years ago
5

If a system has cind independent components, what is the maximum number of phases that can exist in equilibrium? (b) A given sys

tem has eight liquid phases in equilibrium with each other. What must be true about the number of independent components in this system?
Chemistry
1 answer:
stellarik [79]2 years ago
7 0

Answer:

a) the maximum number of phases that can exist in equilibrium is c_{ind + 2

b) the number of independent components in this system are 6

Explanation:

We know that, The degree of freedom f for a system can be simply referred to as number of variables that must be defined to completely solve a system.

If degree of freedom is 0, then any problem is can be solved.

a) If a system has cind independent components, what is the maximum number of phases that can exist in equilibrium?

The degree of freedom for a system can be written as;

f = c_{ind - p + 2

where f is the degree of freedom

c_{ind is the number of independent component

so we solve for c_{ind

c_{ind = f + p - 2

we know that f can not be less than 0

Hence maximum possible face will be;

c_{ind = p - 2

p = c_{ind + 2

Therefore, the maximum number of phases that can exist in equilibrium is c_{ind + 2

b) A given system has eight liquid phases in equilibrium with each other. What must be true about the number of independent components in this system?

Number of phases in the system p = 8

p = c_{ind + 2

c_{ind = p - 2

we substitute

c_{ind = 8 - 2

c_{ind = 6

Therefore, the number of independent components in this system are 6

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3 years ago
It asks for the percentage but I’m not sure how to find it when the answer is 67.1%
Vlada [557]
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sergey [27]

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Solvent: water

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We convert the solute's mass  to moles → 10.7 g / 120.36 g/mol = 0.089 moles

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Answer:

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