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3 years ago

What was the greatest discovery by galileo during his inclined-plane experiments?

1 answer:

3 0

Galileo discovered during his inclined-plane experiments that a ball rolling down an incline and onto a horizontal surface would roll indefinitely.

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Sally accelerates a 250 kg cart at 3 m/s/s. What must be

Arisa [49]

Net force = mass x acceleration = 250 x 3 = 750 N

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3 years ago

To form a negative ion, an atom will give up an electron to gain stability <br><br> True or False?

Mumz [18]

It is a completely false statement that to form a negative ion, an atom will <span>give up an electron to gain stability. The correct option among all the options that are given in the question is the second option. Negative ion has more electrons and so it would be wrong to say that it will give up an electron. I hope the answer has helped you.
</span>

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3 years ago

Is there proof of the existence of God and Satan?If so what proof?

ivolga24 [154]

Religiously it has been proved that God exist and even satan exist
scientist does not believe God exist.The big bang theory is a theory that postulated that a big bang occur when and everything but my proverb says "in a film there is always behind the scene" if God doesnt exist who created mountains,hills,rivers,oceans,man,animal,spirit and if satan doesnt exist why does hell exist but if God doesnt exist why is it in grammar law to use capital letter for God
but my advise for you is to ask God to show you if He truly exist

3 0

4 years ago

A 15g bullet is fired horizontally into a 3kg block of wood suspended by a long cord. Assume that the bullet remains in the bloc

Varvara68 [4.7K]

Answer:

261.3 m/s

Explanation:

Mass of bullet=m=15 g= $\frac{15}{1000}=0.015 kg$

1 kg=1000g

Mass of block=M=3 kg

d=0.086 m

Total mass =M+m=3+0.015=3.015 kg

K.E at the time strike=Gravitational potential energy at the end of swing

$\frac{1}{2}(m+M)^2V^2=(m+M)gh$

Using g= $9.8m/s^2$

Substitute the values

$\frac{1}{2}(3.015)V^2=3.015\times 9.8\times 0.086$

$V^2=\frac{2\times 3.015\times 9.8\times 0.086}{3.015}$

$V=\sqrt{2\times 3.015\times 9.8\times 0.086}}$

$V=1.3m/s$

Velocity after collision=V=1.3 m/s

Velocity of block=v'=0

Using conservation law of momentum

$mv+Mv'=(m+M)V$

Using the formula

$0.015v+3(0)=3.015(1.3)$

$0.015v=3.015(1.3)$

$v^2=\frac{3.015(1.3)}{0.015}=261.3$

$v=261.3 m/s$

5 0

4 years ago

How much power does it take to lift a 30.0 n box 10.0 m high in 5.00 s, if you must apply a 62n force to lift the box?

Illusion [34]

Power is defined as the rate at which the body is doing work:
$P=\frac{W}{t}$
Work is defined as displacement done by the force times that displacement:
$W=F\cdot h$
We know that we need 62N to move the box, so when we apply this force along the path of 10m we have done:
$W=62N\cdot10m=620J$
of work.
Now we just divide that by 5s to get how much power is required:
$P=\frac{620J}{5s}=124W$

5 0

3 years ago