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Nikitich [7]
3 years ago
9

A football player kicks a ball with a mass of 0.42 kg. The average acceleration of the football was 14.8 m/s².

Physics
2 answers:
kvasek [131]3 years ago
6 0
D.6.22N. because .42kg * 14.8m/s=6.22 N[meaning newtons}.
Mamont248 [21]3 years ago
4 0

Explanation:

The correct answer is: (Option D) 6.22 N

Explanation:

By using the <em>Newton's second law</em>:

<em>F = m*a --- (A)</em>

F = Force = ?

m = mass = 0.42 kg

a = acceleration = 14.8 \frac{m}{s^2}

Plug the values in equation (A):

F  = 0.42 * 14.8

F = 6.216 N

F \approx 6.22 N (Option D)

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charle [14.2K]
The law of conservation of energy<span>, a fundamental concept of physics, states that the total amount of </span>energy<span> remains constant in an isolated system. It implies that </span>energy<span> can neither be created nor destroyed, but can be change from one form to another.</span>
6 0
3 years ago
A car runs for about 10 years during its average useful life. If the odometer reads 120,000 miles at the end, what was the avera
Eva8 [605]

Answer:

12000 mph

Explanation:

Given that,

Distance read by the odometer = 120,000 miles

Duration of car, t = 10 years

We need to find the average speed of the car. Speed of an object is equal to the total distance covered divided by total time taken. So,

v=\dfrac{120000}{10}\\\\=12000\ mph

So, the average speed of the car is 12000 mph.

7 0
3 years ago
A piano tuner is using a 392 Hz tuning fork to tune the wire for a G-Natural note. She hears 4 beats per second. What are the tw
inysia [295]

A beat is an interference pattern between two sounds of slightly different frequencies, perceived as a periodic variation in volume whose rate is the difference of the two frequencies. Frequency beat is equal to,

f_{beat} =| f_2\pm f_1 |

The reference frequency in our case would be 392Hz, and since there is the possibility of the upper and lower range for the amount of beats per second that the two possible frequencies are heard would be

f_{beat} =|392+4|= 396Hz

f_{beat} =|392-4|=388Hz

Therefore the two possible frequencies the piano wire is vibrating at, would be 396Hz and 388Hz

5 0
3 years ago
You go to the hardware store to buy a new 50 ft garden hose. You find you can choose between hoses of ½ inch and 5/8 inch inner
omeli [17]

To solve this problem it is necessary to consider two concepts. The first of these is the flow rate that can be defined as the volumetric quantity that a channel travels in a given time. The flow rate can also be calculated from the Area and speed, that is,

Q = V*A

Where,

A= Cross-sectional Area

V = Velocity

The second concept related to the calculation of this problem is continuity, which is defined as the proportion that exists between the input channel and the output channel. It is understood as well as the geometric section of entry and exit, defined as,

Q_1 = Q_2

V_1A_1=V_2A_2

Our values are given as,

A_1=\frac{1}{2}^2*\pi=0.785 in^2

A_2=\frac{5}{8}^2*\pi=1.227 in^2

Re-arrange the equation to find the first ratio of rates we have:

\frac{V_1}{V_2}=\frac{A_2}{A_1}

\frac{V_1}{V_2}=\frac{1.227}{0.785}

\frac{V_1}{V_2}=1.56

The second ratio of rates is

\frac{V2}{V1}=\frac{A_1}{A2}

\frac{V2}{V1}=\frac{0.785}{1.227}

\frac{V2}{V1}=0.640

3 0
4 years ago
A string has an abrupt change in linear density at its midpoint so that the speed of a pulse on the left side is 2/3 of that on
goldenfox [79]

Answer:

Explanation:

a) Linear density is greater on the left side because the velocity of wave in a string is inversely proportional to the linear mass density of the string

b) We should start pulse from the left hand side so the reflected wave does not get inverted because the wave traveling from the denser to lighter medium gets reflected in the same phase.

3 0
3 years ago
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