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Nikitich [7]
3 years ago
9

A football player kicks a ball with a mass of 0.42 kg. The average acceleration of the football was 14.8 m/s².

Physics
2 answers:
kvasek [131]3 years ago
6 0
D.6.22N. because .42kg * 14.8m/s=6.22 N[meaning newtons}.
Mamont248 [21]3 years ago
4 0

Explanation:

The correct answer is: (Option D) 6.22 N

Explanation:

By using the <em>Newton's second law</em>:

<em>F = m*a --- (A)</em>

F = Force = ?

m = mass = 0.42 kg

a = acceleration = 14.8 \frac{m}{s^2}

Plug the values in equation (A):

F  = 0.42 * 14.8

F = 6.216 N

F \approx 6.22 N (Option D)

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Answer:

The range of angles is from 17.50° to 31.76°

Explanation:

The diffraction grid equation is as follows:

dsen\theta=m\lambda

Clearing for \theta

sen\theta=\frac{m\lambda}{d}

\theta=sen^{-1}(\frac{m\lambda}{d})

where \theta is the angle, m is the order, in this case m=1, \lambda is the wavelength, and d is defined as follows:

d=\frac{1}{resolution}

and since the resolution is 750 lines/mm wich is the same as 750lines/1x10^{-3}m

d will be:

d=\frac{1}{750lines/1x10^{-3}m}=\frac{1x10^{-3}m}{750lines}=1.33x10^{-6}m

wich is the distance between each line of the diffraction grating.

substituting the values for m and d:

\theta=sen^{-1}(\frac{(1)\lambda}{(1.33x10^{-6}m)})

And we need to find two angle values: one for when the wavelength is 400nm and one for when it is 700 nm. So we will get the angle range

\theta=sen^{-1}(\frac{(400x10^{-9})}{(1.33x10^{-6}m)})=17.50

and

\theta=sen^{-1}(\frac{(700x10^{-9})}{(1.33x10^{-6}m)})=31.76

The range of angles is from 17.50° to 31.76°

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