<h2>Amoeba / Unicellular</h2><h2>Segmented worm / Earthworm</h2><h2>Unsegment worm / Tapeworm</h2><h2>Snail / Molluscs</h2><h2>Butterfly / A pair of antenna</h2><h2 /><h3><em>Unicellular: </em><u><em>aboema</em></u><em>: a </em><u><em>one-celled</em></u><em>, microscopic organism belonging to any of several families of rhizopods that move and feed using pseudopodia and reproduce by fission</em></h3><h3><em /></h3><h3><em>Segmented worms: segmented worms include the common </em><u><em>earthworm</em></u><em> and leeches.</em></h3><h3><em /></h3><h3><u><em>Unsegented worms:</em></u><em> unsegmented Worms Phylum Platyhelminthes & Nematoda. Worms. Worms are divided into three different phyla: Phylum Platyhelminthes, the flatworms. These include marine flatworms, flukes, and </em><u><em>tapeworms</em></u><em>.</em></h3><h3><em /></h3><h3><u><em>Molluscs</em></u><em>: molluscs examples: – </em><u><em>snails</em></u><em>, slugs, limpets, whelks, conchs, periwinkles, etc. Class Bivalvia – clams, oysters, mussels, scallops, cockles, shipworms, etc. The Class Scaphopoda contains about 400 species of molluscs called tooth or tusk shells, all of which are marine.</em></h3><h3><em /></h3><h3><u><em>Antennas</em></u><em>: </em><u><em>Nearly all insects have a pair of antennae</em></u><em> on their heads. They use their antennae to touch and smell the world around them. ... Insects are the only arthropods that have wings, and the wings are always attached to the thorax, like the legs.</em></h3>
Answer:
W= 4.89 KJ
Explanation:
Lets take
temperature of hot water T₁ = 100⁰C
T₁ = 373 K
Temperature of cold ice T₂= 0⁰C
T₂ = 273 K
The latent heat of ice LH= 334 KJ
The heat rejected by the engine Q= m .LH
Q₂= 0.04 x 334
Q₂= 13.36 KJ
Heat gain by engine = Q₁
For Carnot engine
Q₁ = 18.25 KJ
The work W= Q₁ - Q₂
W= 18.25 - 13.36 KJ
W= 4.89 KJ
Complete Question
A proton is located at <3 x 10^{-10}, -5*10^{-10} , -5*10^{-10}> m. What is r, the vector from the origin to the location of the proton
Answer:
The vector position is 
Explanation:
From the question we are told that
The position of the proton is 
Generally the vector location of the proton is mathematically represented as
So substituting values
Ek = (m*V^2) / 2 where m is mass and V is speed, then we can take this equation and manipulate it a little to isolate the speed.
Ek = mv^2 / 2 — multiply both sides by 2
2Ek = mv^2 — divide both sides by m
2Ek / m = V^2 — switch sides
V^2 = 2Ek / m — plug in values
V^2 = 2*30J / 34kg
V^2 = 60J/34kg
V^2 = 1.76 m/s — sqrt of both sides
V = sqrt(1.76)
V = 1.32m/s (roughly)
