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Ira Lisetskai [31]
3 years ago
12

Pls help it's about density ​

Chemistry
1 answer:
Vaselesa [24]3 years ago
4 0
1. 100.67
2. 168.55
3. 2.747
So I’m not sure if 2 or 3 are right sorry
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How many moles are in 2.5L of 1.75 M Na2CO3
Natasha_Volkova [10]

Answer:

4.4 mol.

Explanation:

Hello!

In this case, since the formula for calculating the molarity is:

M=n/V

Whereas n stands for moles and V for the volume in liters; we can solve for n as shown below when we are given the volume and the molarity:

n=V*M

Thus, we plug in the given data to obtain:

n=2.5L*1.75mol/L=4.4mol

Best regards!

4 0
2 years ago
Read 2 more answers
2) 183 cg =<br> kg<br> 5<br> .00183 kg<br> 0.0183 kg<br> .183 kg<br> 3) 0.25 kg =<br> g
OlgaM077 [116]

Answer:

183 cg = 0.00183 kg

0.25 kg = 250 g

Explanation:

Use conversion factors. 1kg is equal to 1 x 10^5 cg (100000) and 1 kg is equal to 1 x 10^3 grams (1000 grams).

5 0
3 years ago
What mass of H2O is produced by the combustion of 1.00 mol of CH4?
kkurt [141]
CH4 : H2O
1 : 2

number of moles of H2O = 1.00 x 2
number of moles of H2O = 2.00mol

mass = number of moles x molar mass

mass of H2O = 2.00 x (1 + 1 + 16)
mass of H2O = 36g
8 0
2 years ago
If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
Alinara [238K]

Answer:

The value of  the heat capacity of the Calorimeter  C_c = 54.4 \frac{J}{c}

Explanation:

Given data

Heat added Q = 4.168 KJ = 4168 J

Mass of water m_w = 75.40 gm

Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c

From the given condition

Q = m_w C_w ΔT + C_c ΔT

Put all the values in above equation we get

4168 = 75.70 × 4.18 × 11.24 +  C_c × 11.24

611.37 =  C_c × 11.24

C_c = 54.4 \frac{J}{c}

This is the value of  the heat capacity of the Calorimeter.

7 0
3 years ago
What kind of bond is created by a week electrical attraction between polar molecules
Studentka2010 [4]

Answer : The dipole-dipole interaction.

Explanation : The kind of bond that is created by a weak electrical attraction between two polar molecules is dipole-dipole interaction.

The type of force which occurs between the positive end of one molecule and the negative end of another molecule: is dipole-dipole interaction.

For better understanding, please refer the attachment.

8 0
3 years ago
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