<u>11.35 g</u><u> </u><u>atoms </u><u>of lead are in the sample.</u>
What does density mean?
- The density of an area refers to the quantity of things—which may include people, animals, plants, or objects—there are in it.
- Divide the number of objects by the area's measurement to determine density.
- A country's population density is calculated by dividing its total population by its area, expressed in square kilometers or miles.
We can calculate the volume of the cube by cubing the side of the cube.
Volume of cube = ( 1.000 cm)³
= 1.000 cm³
We can now determine the amount of lead in the cube by multiplying by the density. Because we know we have a 1.000 cubic centimeter and that lead has a density of 11.35 grams per cubic centimeter, we have 11.35 grams of lead.
= ( 1.000 cm³) ( 11.35 
)
= 11.35 g
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False heat rises upwards therefore the hottest part of the sun would be upwards
the correct IUPAC name of the compound is 1-Butanal.
<h3>What are IUPAC names?</h3>
It is a system of naming organic compounds based on the longest carbon-to-carbon single bonds. It does not matter whether these longest chains are continuous or in a ring.
Thus, when the compound with the chemical formula, CH3-CH2-CH2CHO is considered. The longest carbon-to-carbon chain is 4. The 1st carbon carries a functional group known as an aldehyde.
Aldehydes are equipped with the carbonyl group and have the general formula R−CH=O. They are also sometimes referred to as formyl.
Aldehydes are named after their parent alkane chains with a slight modification. The 'e' is replaced with 'al'
The aldehyde in this case has four carbons. This means that the parent alkane is Butane. Therefore, the name of the compound will be 1-Butanal.
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The energy of the carbide released is 7262.5MJ.
<h3>What is the energy?</h3>
We know that the reaction between calcium oxide and carbon occurs in accordance with the reaction; 
. The reaction is seen to produce 464.8kJ of energy per mole of carbide produced.
Number of moles of 
produced = 1000 * 10^3 g/64 g/mol
= 15625 moles of calcium carbide
If 1 mole of transfers 464.8 * 10^3 J
15625 moles of calcium carbide transfers 15625 moles * 464.8 * 10^3 J/ 1 mol
= 7262.5MJ
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