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love history [14]
2 years ago
11

What makes a cyclone rotate counter-clockwise north of the Equator and clockwise south of the Equator?

Chemistry
2 answers:
julia-pushkina [17]2 years ago
8 0

The Coriolis Effect (Core-nol-e-us)

saw5 [17]2 years ago
5 0
The ocean currents move differently on both equator‘s so it makes the cyclones rotate different
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Suppose you work at a theme park. Your supervisor wants you to make a sign displaying the maximum weight that a roller coaster t
grin007 [14]

Answer:

amusement parks. Each day, we flock by the millions to the nearest park, paying a sizable hunk of money to wait in long lines for a short 60-second ride on our favorite roller coaster. The thought prompts one to consider what is it about a roller coaster ride that provides such widespread excitement among so many of us and such dreadful fear in the rest? Is our excitement about coasters due to their high speeds? Absolutely not! In fact, it would be foolish to spend so much time and money to ride a selection of roller coasters if it were for reasons of speed. It is more than likely that most of us sustain higher speeds on our ride along the interstate highway on the way to the amusement park than we do once we enter the park. The thrill of roller coasters is not due to their speed, but rather due to their accelerations and to the feelings of weightlessness and weightiness that they produce. Roller coasters thrill us because of their ability to accelerate us downward one moment and upwards the next; leftwards one moment and rightwards the next. Roller coasters are about acceleration; that's what makes them thrilling. And in this part of Lesson 2, we will focus on the centripetal acceleration experienced by riders within the circular-shaped sections of a roller coaster track. These sections include the clothoid loops (that we will approximate as a circle), the sharp 180-degree banked turns, and the small dips and hills found along otherwise straight sections of the track.

3 0
1 year ago
In Atomic Absorption Spectrophotometry, narrow atomic lines are desirable. However, line broadening arises from: (a) Jablonski e
LenKa [72]

Answer: b) Doppler Effect

Explanation:

Line broadening in AAS, arises due to some effects, which can occur due to a number of factors. The line width broadening effects include: Doppler, Lorentz, Self absorption, and quenching effects.

Doppler effect arises because along the line of observation, atoms will have different components of velocity.

7 0
3 years ago
A bus travels 20km in 30 min what is the average speed of the bus
STatiana [176]

Answer:

40km/h

Explanation:

v=20km/0.5h=40km/h.

5 0
3 years ago
Read 2 more answers
Which compound is an exception to the octet rule
anyanavicka [17]

I think it's RbCl and CaO
7 0
3 years ago
A unit of heat energy that was formerly used frequently was the calorie. Look up the definition of the calorie in your textbook
dybincka [34]

Answer and Explanation:

Calorie is the unit of heat energy . There are 2 units with the same name 'calorie' which is widely used.

'The amount of heat energy required to increase the temperature of 1 gram of water by mass by 1^{\circ}C or 1 K is known as small calorie or gram calorie'.

Another one is large calorie which can be defined as :

'The amount of heat energy required to make arise in temperature of water 1 kg by mass by 1^{\circ}C or 1 K is known as large calorie or  kilcalorie and is represented as Cal or kcal'.

After the adoption of SI system, thee units of the metric system cal, C or kilocal are considered deprecated or obsolete with the SI unit for heat energy as 'joule or J'

1 cal = 4.184 J

1C or 1 kilocal = 4184 J

Calorimeter constant:

Calorimeter constant, represented as 'C_{cal}' is used to quantify the heat capacity or the amount of heat of a calorimeter.

It can be calculated by ther given formula:

{\displaystyle C_{cal}}={\frac {\Delta {H}}{\Delta {T}}}}}

where,

{\Delta {T}} = corresponding temperature change

{\Delta {H} = enthalpy change

Its unit is J/K or J/1^{\circ}C[/tex] which can be convertyed to cal/1^{\circ}C[/tex] by dividing the calorimeter constant by 4.184 or 4184 accordingly.

8 0
3 years ago
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