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Tju [1.3M]
2 years ago
9

For the reaction below , label each reactant as an electron pair acceptor or electron pair donor and as a Lewis acid or a Lewis

base. AlCl 3 +Cl^ -; AlCl 4 ^ -
Chemistry
1 answer:
JulsSmile [24]2 years ago
6 0

Since the reaction shown in the question is an acid - base reaction in the Lewis sense; the Lewis acid here is AlCl3  while the Lewis base here is Cl^- .

<h3>What is  a Lewis acid?</h3>

A Lewis acid is a substance that accepts electron pair while a Lewis base donates an electron pair.

Now consider the given reaction; AlCl3 +Cl^- ------> AlCl 4 ^-. The Lewis acid here is AlCl3  while the Lewis base here is Cl^- .

Learn more about acid - base reaction: brainly.com/question/14356798

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2 years ago
Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.
Colt1911 [192]

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\%C_E = \frac{E}{T} * 100\%

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In (Ca(OH)_2)

The amount of all elements is: (i.e formula mass of (Ca(OH)_2))

T = 1 * Ca + 2 * H + 2 * O

T = 1 * 40 + 2 * 1 + 2 * 16

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The amount of calcium is: (i.e formula mass of calcium)

E = 1 * Ca

E = 1 * 40

E = 40

So, the percentage component of calcium is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{40}{74} * 100\%

\%C_E = \frac{4000}{74}\%

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The amount of hydrogen is:

E = 2 * H

E = 2 * 1

E = 2

So, the percentage component of hydrogen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{2}{74} * 100\%

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\%C_E = 2.70\%

Similarly, for oxygen:

The amount of oxygen is:

E = 2 * O

E = 2 * 16

E = 32

So, the percentage component of oxygen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{32}{74} * 100\%

\%C_E = \frac{3200}{74}\%

\%C_E = 43.24\%

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2 years ago
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ddd [48]

Answer:

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Explanation:

Hope this helped! Stay safe and goodluck on what you're doing! ♥♥♥

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