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forsale [732]
4 years ago
9

A substance is known to contain 2.00 g of carbon for every 5.33 g of oxygen. How many grams of carbon will be present in 55.0 g

of this substance?
Chemistry
2 answers:
nexus9112 [7]4 years ago
8 0
First, set up a proportion:
You have 2.00 g Carbon and 7.33 g of the total substance (find it by adding 2.00g C + 5.33 g O)
You have an unknown g carbon with 55.0 g o total substance.

So:
\frac{2.00}{7.33}  =  \frac{x}{55.0}

Multiply 2.00 by 55.0 and divide the answer by 7.33 
You'll get 20.63...


tiny-mole [99]4 years ago
7 0

Answer : The mass of carbon present in 55.0 grams of the substance will be, 15.006 grams.

Explanation :

First we have to calculate the total mass substance.

Total mass of substance = Mass of carbon + Mass of oxygen

Total mass of substance = 2.00 g + 5.33 g = 7.33 g

Now we have to calculate the mass of carbon present in 55.0 grams of substance.

As, 7.33 grams of substance contain 2.00 grams of carbon.

So, 55.0 grams of substance contain \frac{2.00}{7.33}\times 55.0=15.006 grams of carbon.

Therefore, the mass of carbon present in 55.0 grams of the substance will be, 15.006 grams.

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Travka [436]

Answer:

no answer

Explanation:

because he knew that eventually other elements would be discovered to fit into those spaces. The elements in the same group or column have similar properties.

5 0
3 years ago
Calculate the final temperature of 35 mL of ethanol initially at 20 ∘C upon absorption of 720 J of heat. (density of ethanol =0.
Natalija [7]
The specific heat capacity of ethanol is 2.46 joules per gram.
Now, we may use the equation:
Energy = mass * specific heat capacity * change in temperature

Here we may substitute:
mass = density * volume

Energy = density * volume * specific heat capacity * change in temperature
720 = 0.789 * 35 * 2.46 * ΔT
ΔT = 10.6

The final temperature will be
20 + 10.6
= 30.6 °C
4 0
4 years ago
50.0 mL of an HNO3 solution were titrated with 36.90 mL of a 0.100 M LiOH solution to reach the equivalence point. What is the m
Xelga [282]
Following reaction takes place between LiOH and HNO3

LiOH    +  HNO3        →        LiNO3      +       H2O

Thus, 1 mole of LiOH reacts with 1 mole of HNO3 to form 1 mole of LiNO3.

Now, 
Number of millimoles of LiOH consumed = <span>36.90 X 0.100 = 3.690

</span>∴Number of millimoles of HNO3 present = 3.690
<span>
Now, Molarity of HNO3 = </span>\frac{\text{number of millimoles of HNO3}}{\text{volume of solution (ml)}}
                                      =   \frac{3.690}{50} = 0.0738 M

Thus, <span>molarity of the HNO3 solution is 0.0738 M</span>
8 0
3 years ago
In a certain compound of iron and oxygen, FexOy, it is found that a sample of this compound weighing 6.285 g contains 4.396 g of
saveliy_v [14]

Answer:

Formula of oxide is Fe_{2}O_{3}

Explanation:

The given compound consists of Fe and O.

So, mass of oxygen in sample = (mass of sample) - (mass of Fe in sample)

                                                   = (6.285 g ) - (4.396 g)

                                                   = 1.889 g

Molar mass of O = 16 g/mol and molar mass of Fe = 55.845 g/mol

So, ratio of number of moles of Fe and O (Fe : O)

      = \frac{4.396}{55.845}:\frac{1.889}{16}

      = 0.0787 : 0.118

      = 1:\frac{0.118}{0.0787}

      = 1 : 1.5

      = 2 : 3

So, formula of oxide is Fe_{2}O_{3}

5 0
3 years ago
As the atomic numbers of the elements in column IIA increase, the size of the atoms generally
joja [24]

Answer:

Increase

Explanation:

7 0
4 years ago
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