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Valentin [98]
3 years ago
5

In a certain compound of iron and oxygen, FexOy, it is found that a sample of this compound weighing 6.285 g contains 4.396 g of

Fe. What is the formula of the oxide?
Chemistry
1 answer:
saveliy_v [14]3 years ago
5 0

Answer:

Formula of oxide is Fe_{2}O_{3}

Explanation:

The given compound consists of Fe and O.

So, mass of oxygen in sample = (mass of sample) - (mass of Fe in sample)

                                                   = (6.285 g ) - (4.396 g)

                                                   = 1.889 g

Molar mass of O = 16 g/mol and molar mass of Fe = 55.845 g/mol

So, ratio of number of moles of Fe and O (Fe : O)

      = \frac{4.396}{55.845}:\frac{1.889}{16}

      = 0.0787 : 0.118

      = 1:\frac{0.118}{0.0787}

      = 1 : 1.5

      = 2 : 3

So, formula of oxide is Fe_{2}O_{3}

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