Answer: A. 4 unpaired electrons
B. Zero unpaired electrons
C. 1 unpaired electron
D. 5 unpaired electrons
E. Zero unpaired electrons
Explanation:
In A, Oxidation state of Co is +3 and Electronic configuration is [Ar]3d6
F is weak field ligand, causes no pairing of Electrons hence it has 4 unpaired electrons&2 are paired in t2g orbitals (dXY)
In B , Mn is in +3 with electronic configuration 3d4&CN is a strong field ligand hence causes pairing of Electrons hence it results 0 unpaired electron
In C, Mn is in +2 with electronic configuration 3d5 sinceCN is a strong field ligand hence it leaves one unpaired electron
In D, Mn is in+2 with 3d5& five unpaired electrons since cl is a weak field ligand causes no pairing.
In E, Rh is in +3, with d6 configuration and it is a low spin complex hence pairing of Electrons involved. So it leaves zero unpaired electrons.
Formula of sodium phosphate = Na₃PO₄
So, one mole of sodium phosphate molecules have 3 moles of Na atoms
Then, 1.6 moles of Na₃PO₄ will have: 1.6 × 3 = 4.8 moles of sodium atoms will be present
Both have Giant Covalent Structures, resulting in very high melting temperatures. However each carbon atom in Diamond has 4 covalent bonds with other Carbons, making it extremely strong and hard. On the other hand, each carbon in graphite is bonded to three carbons, and therefore graphite is formed in layers.
Sodium Chloride is a example of a ionic bond one atom is positively charged while the other is negatively charged both end up becoming neutral charge after they bond. check my answer to make sure that statement is accurate.
Correct answer: <span>An isomer with a branched structure will require:
less energy to melt than the straight chain structure.
Reason:
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The branched chain compounds have lower melting and boiling points as compared to straight chain isomers.This is due to the fact that branching makes the molecule more compact. This results in decreases in surface area of isomer. But, the intermolecular attractive forces depends on the surface area of compound. Thus, branched isomers have lower intermolecular force of interaction, as compared to straight chain isomers. Consequently, the melting/boiling points of the branched chain isomers are lower as compared to straight chain isomers.