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yawa3891 [41]
3 years ago
9

If a stereo has a dial that changes the volume of the sounds the stereo makes, what is the dial doing? a. changing the number of

times a wave passes by a point b. changing the pitch of the sound waves. c changing the length of the sound waves d. changing the amplitude of the sound waves
Physics
2 answers:
Over [174]3 years ago
8 0
If the stereo has a dial that changes the volume of the sounds the stereo makes, the one that being done by the dial is : D. Changing the amplitude of the sound waves

Hope this helps
babymother [125]3 years ago
6 0

Answer: The correct answer is (d).

Explanation:

The stereo has a dial that changes the volume of the sound the stereo makes.

The intensity of the sound increases with the amplitude of the sound wave. The energy of the sound wave is directly proportional to the amplitude of the wave.

The loudness of the sound increases with increase in the amplitude of the sound wave.

Therefore, the stereo has a dial that changes the volume of the sound the stereo makes. In this case, the dial is changing the amplitude of the sound waves.  

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False they are producers and they don' eat anything only produce and provide

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convection

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2 years ago
A soccer player kicks a rock horizontally off a 37 m high cliff into a pool of water. If the player hears the sound of the splas
Alchen [17]
<h2>Answer:</h2>

<em><u>(a). 16.741 m/s</u></em>

<em><u>(b). 15.75 m/s</u></em>

<h2>Explanation:</h2>

In the question,

Height of the cliff, h = 37 m

Time taken to reach the sound to us = 2.92 s

Speed of the sound in air at room temperature = 343 m/s

Now,

Let us say the speed of the ball = u m/s

So,

Time taken by the ball to reach at the bottom, t is given by,

t=\sqrt{\frac{2h}{g}}\\t=\sqrt{\frac{2\times 37}{9.8}}\\t=2.747\,s

So,

Splash is heard after = 2.92 s

So,

<u>Time taken by sound to travel the shortest distance along the hypotenuse of the triangle</u> thus formed is,

t = 2.92 - 2.747

t = 0.172 s

Now,

Distance traveled by sound is given by,

Distance=343\times 0.172\\Distance=59.02\,m

So,

In the triangle using the Pythagoras Theorem,

Horizontal distance traveled is,

D=\sqrt{59.02^{2}-37^{2}}\\D=45.99\,m

So,

Speed of throwing of ball is given by,

Distance=Speed\times Time\\45.99=u\times 2.747\\u=16.741\,m/s

<em><u>Therefore, the speed of the ball = 16.741 m/s.</u></em>

(b).

If,

Speed of sound = 331 m/s

So,

<u>Distance traveled by sound</u> is,

Distance=331\times 0.172\\Distance=56.932\,m

So,

Distance traveled in the horizontal by ball is,

Distance=\sqrt{56.932^{2}-37^{2}}\\Distance=43.269\,m

So,

Speed of the ball thrown is given by,

Speed=\frac{Distance}{Time}\\Speed=\frac{43.269}{2.747}\\Speed=15.75\,m/s

<em><u>Therefore, the speed of the ball = 15.75 m/s.</u></em>

8 0
3 years ago
You are given two unknown point charges, Q1, and Q2. At a point on the line joining them, one third of the way from Q1 to Q2 the
podryga [215]
The formula that is applicable here is E = kQ/r^2 in which the energy of attraction is proportional to the charges and inversely proportional to the square of the distance. In this case, 
kQ1/(r1)^2 = kQ2/(r2)^2  r1=l/3, r2=2l/3solve Q1/Q2
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