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BaLLatris [955]
3 years ago
11

Instead of rolling down the ramp over the step, imagine the ball falls off the back of the ramp directly to the ground. What is

the amount of potential energy remaining after the ball lands on the ground?
Physics
2 answers:
lesya692 [45]3 years ago
8 0

0J

According to the law of conservation of energy, the potential energy is converted to kinetic energy. Remember, potential energy is calculated using height and weight. If the ball is on the ground, height is 0.

WITCHER [35]3 years ago
6 0
Assuming the ground has 0 height, than there would be no potential energy.
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attashe74 [19]

(a) The momentum of the first trolley is 5.4 kgm/s

(b) The velocity of the trolleys after impact is 2.7m/s

<u>Explanation:</u>

Given:

Mass, m₁ = 1.2kg

Velocity, v₁ = 4.5m/s

Mass, m₂ = 0.8kg

v₂ = 0

(a) Momentum of the trolley before impact, p

We know:

Momentum = mass X velocity

p = 1.2 X 4.5

p = 5.4 kgm/s

Therefore, the momentum of the first trolley is 5.4 kgm/s

(b) Speed of the trolleys after impact, v = ?

During collision, the momentum is conserved.

So,

m₁v₁ + m₂v₂ = (m₁ + m₂)v

(1.2 X 4.5) + (0.8 X 0) = (1.2 +0.8) X v

5.4 + 0 = 2v

v = 2.7m/s

Therefore, the velocity of the trolleys after impact is 2.7m/s

8 0
3 years ago
Nearly all physics problems will use the unit m/s^2 for acceleration. Explain why the seconds are squared. Why isn't the unit gi
sertanlavr [38]

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The magnitude (size) part of acceleration is:

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Are you speeding up ?
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Then your acceleration is

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When you write that phrase as an algebraic expression, it's

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Andreas93 [3]
The correct answer is kilograms
6 0
2 years ago
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Kipish [7]

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