Given:
F = 39 N, the force applied
t = 2 s, the time interval in which the force is applied.
By definition, the impulse is
Answer: 78 N-s
Answer:
x = 0.974 L
Explanation:
given,
length of inclination of log = 30°
mass of log = 200 Kg
rock is located at = 0.6 L
L is the length of the log
mass of engineer = 53.5 Kg
let x be the distance from left at which log is horizontal.
For log to be horizontal system should be in equilibrium
∑ M = 0
mass of the log will be concentrated at the center
distance of rock from CM of log = 0.1 L
now,
∑ M = 0
x = 0.974 L
hence, distance of the engineer from the left side is equal to x = 0.974 L
According to newton's law Force = mass * acceleration
so , 100 = 50 * a
so , a= 2 m/s^2
No i took the test and the answer is actually homogenous mixture
