Answer:
helloooooo
look slope is
delta y / delta x
y2 - y1 / x2 - x1
look at the figure i attached i took any random 2 points and drew line till the x and y axes as it is straight line slope is constant we can take any 2 points
so as per points i took
( 8-4 ) / ( 2-4 )
4/-2 = -2
so slope is -2 which is constant throughout
brainliest pweaseeee
Answer:
The funda mental frequency of the original tube is 182Hz.
Explanation:
See the attachment for the calculation steps.
In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.
For closed tubes
f = nv/4L (n = 1, 3, 5,...n)
f = nv/2L (n = 1, 2, 3,...n)
The details of calculation can be found below in the attachment.
Answer:
c.
Explanation:
Initial velocity of cheetah,u=1 m/s
Time taken by cheetah =4.8 s
Final velocity of cheetah,v=28 m/s
We have to find the acceleration of this cheetah.
We know that
Acceleration,
Where v=Final velocity of object
u=Initial velocity of object
t=Time taken by object
Using the formula
Then, we get
Acceleration, a=
Acceleration=
Hence, the acceleration of cheetah=
Answer:
Leak 1 = 3.43 m/s
Leak 2 = 2.42 m/s
Explanation:
Given that the top of the boot is 0.3 m higher than the leaks.
Let height H = 0.3m and the acceleration due to gravity g = 9.8 m/s^2
From the figure, the angle of the leak 1 will be approximately equal to 45 degrees. While the leak two can be at 90 degrees.
Using the third equation of motion under gravity, we can calculate the velocity of leak 1 and 2
Find the attached files for the solution and figure
Answer:
Caustic soda would be least affected by a gas curtailment
Explanation:
Let,
X1= ammonia
X2= ammonium phosphate
X3= ammonium nitrate
X4 = Urea
X5= hydro-fluoric acid
X6= Chlorine
X7= Caustic soda
X8= Vinyl chloride monomer.
Agri chem’s current natural gas usage
= (1200 × 8 + 540 × 10 + 490 × 12 + …)
= 85,680,000 cu. ft. per day
When, the curtailment is 20%, availability is
= 0.8 X 85,680
= 68,554,000 cu. ft. per day
Therefore, the gas constant
= 8X1 + 10X2 + 12X3 + 12X4 + 7X5 + 18X6 + 20X7 + 14X8 ≤68,544
When, the curtailment is 40% availability is
= 0.6 X 85,680
= 51,408,000 cu. ft. per day
Constant = 8X1 + 10X2 + 12X3 + 12X4 + 7X5 + 18X6 + 20X7 + 14X8≤ 51,408
