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disa [49]
3 years ago
15

Can anyone help??????????????

Physics
1 answer:
DerKrebs [107]3 years ago
3 0

I think the answer should be the last one. Magnets attract magnets with unlike poles and repel magnets with like poles

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Two<br>vectors Å and °B are such that A = 2<br>and A-B-C find the angle between them​
sweet-ann [11.9K]

Answer:

hjg567 A 567

Explanation:

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3 years ago
A train travels southwest from point A to point B through the Arizona desert at 55 mi/h. How far will the train travel six-and-a
TiliK225 [7]

Explanation:

Distance = speed × time

d = (55 mi/hr) (6.5 hr)

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When an ocean plate converges with another plate, what is created on the seafloor at the line of convergence?
drek231 [11]
When two oceanic plates meet, the process of subduction occurs. During this, the denser plate slips underneath the lighter one, creating a subduction zone. In these subduction zones, a trench is formed. 
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3 years ago
If a car is taveling with a speed 6 and comes to a curve in a flat road with radius ???? 13.5 m, what is the minumum value the c
Lemur [1.5K]

Answer:

\mu_s \geq 0.27

Explanation:

The centripetal force acting on the car must be equal to mv²/R, where m is the mass of the car, v its speed and R the radius of the curve. Since the only force acting on the car that is in the direction of the center of the circle is the frictional force, we have by the Newton's Second Law:

f_s=\frac{mv^{2}}{R}

But we know that:

f_s\leq \mu_s N

And the normal force is given by the sum of the forces in the vertical direction:

N-mg=0 \implies N=mg

Finally, we have:

f_s=\frac{mv^{2}}{R}  \leq \mu_s mg\\\\\implies \mu_s\geq \frac{v^{2}}{gR}  \\\\\mu_s\geq \frac{(6\frac{m}{s}) ^{2}}{(9.8\frac{m}{s^{2}})(13.5m) }\\\\\mu_s\geq0.27

So, the minimum value for the coefficient of friction is 0.27.

4 0
3 years ago
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The unit 'mb' means millibar which is equivalent to 1/1000 of 1 bar. To convert the units from bar to atmospheres (atm) and to inches Hg (inHg), we need to know the conversion factors.

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0.92 mb(1 bar/1000 mbar)(1 atm/1.01325 bar) =<em> 9.08×10⁻⁴ atm</em>

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0.92 mb(1 bar/1000 mbar)(29.53 inHg/1 bar) =<em> 0.027 inHg</em>
3 0
3 years ago
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