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rjkz [21]
3 years ago
9

If the amplitude of a wave increases by a factor of 4, how is the intensity changed?

Physics
2 answers:
Brut [27]3 years ago
8 0
The intensity increases 16 times.

The relationship between intensity and amplitude is given below:

<span>   I = constant A^{2}

Since, A becomes 4 times, A' = 4A</span><span>
Thus the intensity becomes, I' = constant </span>× (<span>4A)</span>²<span> 
                                              
                                         </span>⇒<span> I' = 16A</span>²

Therefore, the intensity of the wave is increased by 16 times
Kamila [148]3 years ago
6 0

the intensity of the wave is increased by 16 times

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Will mark as brainliest if correct!!!!!!!
lutik1710 [3]

C. A could be ruby (speed of light = 170,000 km/s); B could be diamond (speed of light = 120,000 km/s).

Explanation:

Refraction is a phenomenon that occurs when a light rays crosses the boundary between two different mediums.

When this occurs, the light wave changes speed and also direction, according to Snell's law:

n_1 sin \theta_1 = n_2 sin \theta_2 (1)

where

n_1 is the index of refraction of the first medium

n_2 is the index of refraction of the second medium

\theta_1 is the angle of incidence (the angle between the incident ray and the normal to the boundary)

\theta_2 is the angle of refraction (the angle between the refracted ray and the normal to the boundary)

The index of refraction is the ratio between the speed of light in a vacuum (c) and the speed of light in the medium (v):

n=\frac{c}{v}

Using this definition, we can rewrite eq.(1) as

\frac{\sin \theta_2}{\sin \theta_1} = \frac{v_2}{v_1}

Where v_2 is the speed of light in the 2nd medium and v_1 the speed of light in the 1st medium.

Now let's analyze the situation represented in the figure: we see that as the light ray enters the 2nd medium, it bends towards the normal, this means that the angle of refraction is smaller than the angle of incidence:

\theta_2 < \theta_1

This means that

\frac{\sin \theta_2}{\sin \theta_1}

And therefore,

\frac{v_2}{v_1}

So, the speed of light in the second medium is smaller than the speed of light in the first medium: this occurs only in option C), which is therefore the correct choice.

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

6 0
4 years ago
What are some resources used to generate electricity in energy stations?
Setler79 [48]

--  Coal
--  Oil
--  Natural gas
--  Falling water
--  Sunlight
--  Nuclear fission of Uranium

3 0
3 years ago
Find the resistance of a wire of length 0.65m, 0.2mm and resistivity 3X10^-6 ohm metre.​
const2013 [10]

Answer:

hope this is help full

7 0
3 years ago
PLEASE HELPPPPPPP!!!!!!!!!!
natka813 [3]

Answer:

F' = 800 N

Explanation:

The electrical force between charges is 400 N.

The electrical force between two charges is given by :

F=k\dfrac{q_1q_2}{r^2}

If q₁' = 2q₁, new force becomes,

F'=k\dfrac{q_1'q_2'}{r^2}\\\\F'=k\dfrac{2q_1\times q_2}{r^2}\\\\F'=2\times F\\\\F'=2\times 400\\\\F'=800\ N

So, the new force becomes 800 N.

8 0
3 years ago
What exercise will strengthen your legs?
Olin [163]

Answer: Squats and leg lifts

Explanation:

They strengthen your legs!

7 0
3 years ago
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