Explanation:
(a) The molecular equations shows the equation in which all the species of the reactants and the products are in molecules and the net charge is zero.
The complete ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and are represented as ions.
The net ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and do not show the spectator ions which are same in the reactants and the products.
(b) If there is no spectator ions in the reaction, then the complete and the net ionic equations would be identical.
Answer:
~1.417M
Explanation:
Molarity=(number of moles of solute)/(litres of solution)
In this case, we need to find moles of potassium bromide.
Mass=25.3g
Molar mass= 119g/mol
moles=(mass/molar mass)
=(25.3)/(119)
=0.2126moles of potassium bromide
Molarity=(0.2126)/(150/1000)
~1.417M
Hope this helps:)
Answer:
2NaOH + (NH4) 2SO4 = Na2SO4(s) + 2NH3(g) + 2H2O(l)
Two moles of sodium hydroxide reacts with 1 Mike of ammonium sulphate to give 1 mole of Sodium sulphate, 2 moles of ammonia gas and 2 moles of water
Explanation:
Answer:
The mass of NaCl is 0.029 grams
Explanation:
Step 1: Data given
Molecular weight of NaCl = 58.44 g/mol
Volume of solution = 100 mL = 0.100 L
Molarity = 0.0050 M
Step 2: Calculate moles NaCl
Moles NaCl = molarity * volume
Moles NaCl = 0.0050 M * 0.100 L
Moles NaCl = 0.00050 moles
Step 3: Calculate mass NaCl
Mass NaCl = moles NaCl * molar mass NaCl
Mass NaCl = 0.00050 moles * 58.44 g/mol
Mass NaCl = 0.029 grams
The mass of NaCl is 0.029 grams
