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2 years ago

A word of equationn for the reacyion between lithium and water

Chemistry

1 answer:

Elenna [48]2 years ago

4 0

Answer:

Equation: - 2Li + H2O = Li2O + H2 Uncoated lithium metal reacts with water to form a colorless lithium hydroxide solution and hydrogen gas.

Explanation:

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A chemistry student was asked to calculate the number of moles of iron required to react with 1.20 mol of oxygen to produce iron

Delicious77 [7]

Answer:Write and balance the equation

4Fe + 3O2 -> 2Fe2O3

0.32 mol Fe x 2 mol Fe2O3 / 4 mol Fe =

0.16 mol of Fe2O3

Explanation:

8 0

2 years ago

4. If the DNA nitrogen bases were TACCGGAT, how would the other half of

Illusion [34]

Answer:

ATGGCCTA

Explanation:

For this we have to keep in mind that we have a specific relationship between the nitrogen bases:

-) When we have a T (thymine) we will have a bond with A (adenine) and viceversa.

-) When we have C (Cytosine) we will have a bond with G (Guanine) and viceversa.

Therefore if we have: TACCGGAT. We have to put the corresponding nitrogen base, so:

TACCGGAT

ATGGCCTA

I hope it helps!

3 0

2 years ago

2) If 100.0 J of heat are added to 20.0 g of water at 30.0°C, what will be the final

anzhelika [568]

The final temperature of the water will be 31.2 °C... i don’t know the second one sorry :(

3 0

2 years ago

What is the mass of a 300 ml sample of gaseous hydrogen chloride at 2.0 atm and 30c?

kap26 [50]

Use PV = nRT
(2 atm)(.3 liters) = n(8.314 mol*K)(303°K)

.6 = n(2519.142)

Divide by 2519.142

n = .00023818 mols of HCl * 36.46g of HCl/ 1 mol of HCl

Grams of HCl = 0.00868

3 0

2 years ago

The pH of 0.10 M solution of an acid is 6. What is the acid dissociation constant of the acid?

svlad2 [7]

Answer: Dissociation constant of the acid is $10^{-11}$ .

Explanation: Assuming the acid to be monoprotic, the reaction follows:

$HA\rightleftharpoons H^++A^-$

pH of the solution = 6

and we know that

$pH=-log([H^+])$

$[H^+]=antilog(-pH)$

$[H^+]=antilog(-6)=10^{-6}M$

As HA ionizes into its ions in 1 : 1 ratio, hence

$[H^+]=[A^-]=10^{-6}M$

As the reaction proceeds, the concentration of acid decreases as it ionizes into its ions, hence the decreases concentration of acid at equilibrium will be:

$[HA]=[HA]-[H^+]$