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Shtirlitz [24]
2 years ago
15

One of the nuclides in spent nuclear fuel is U-235 , an alpha emitter with a half-life of 703 million years. How long will it ta

ke for an amount of U-235 to reach 29.0% of its initial amount
Chemistry
1 answer:
sergey [27]2 years ago
8 0

It will take 1.254 billion years to reach 29% of the original amount of U-235.

<h3>First-order Radioactive Decay:</h3>

The rate constant can be calculated from the half-life. The relationship of the two is shown below:

t_{0.5} =\frac{In 2}{k}

k=\frac{In 2}{703}

 = 9.86 × 10 ^-^{4} my^{-1}

The first-order integrated rate law of a nuclide undergoing radioactive decay is;

ln[A]_t = -kt + ln[A]_0.

ln 0.29 = ln1 - 9.86 × 10^-^4 t

ln0.29= -9.86 × 10^-^4

t= 1254.5 my

It will take 1.254 billion years to reach to 29% of the original amount.

Learn more about radioactive decay here:

brainly.com/question/9932896

#SPJ4

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Isotopes of an element share the same number of protons but have different numbers of neutrons. Let's use carbon as an example. There are three isotopes of carbon found in nature – carbon-12, carbon-13, and carbon-14. All three have six protons, but their neutron numbers - 6, 7, and 8, respectively - all differ.

Explanation:

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3 years ago
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What are 3 household substances that contain acids and say why are they useful​
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3 years ago
A reaction was performed in which 3.6 g 3.6 g of benzoic acid was reacted with excess methanol to make 1.3 g 1.3 g of methyl ben
Anit [1.1K]

<u>Answer:</u> The percent yield of the reaction is 32.34 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For benzoic acid:</u>

Given mass of benzoic acid = 3.6 g

Molar mass of benzoic acid = 122.12 g/mol

Putting values in equation 1, we get:

\text{Moles of benzoic acid}=\frac{3.6g}{122.12g/mol}=0.0295mol

The chemical equation for the reaction of benzoic acid and methanol is:

\text{Benzoic acid + methanol}\rightarrow \text{methyl benzoate}

By Stoichiometry of the reaction

1 mole of benzoic acid produces 1 mole of methyl benzoate

So, 0.0295 moles of benzoic acid will produce = \frac{1}{1}\times 0.0295=0.108 moles of methyl benzoate

  • Now, calculating the mass of methyl benzoate from equation 1, we get:

Molar mass of methyl benzoate = 136.15 g/mol

Moles of methyl benzoate = 0.0295 moles

Putting values in equation 1, we get:

0.0295mol=\frac{\text{Mass of methyl benzoate}}{136.15g/mol}\\\\\text{Mass of methyl benzoate}=(0.0295mol\times 136.15g/mol)=4.02g

  • To calculate the percentage yield of methyl benzoate, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of methyl benzoate = 1.3 g

Theoretical yield of methyl benzoate = 4.02 g

Putting values in above equation, we get:

\%\text{ yield of methyl benzoate}=\frac{1.3g}{4.02g}\times 100\\\\\% \text{yield of methyl benzoate}=32.34\%

Hence, the percent yield of the reaction is 32.34 %

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3 years ago
Nitrogen is a group 15 element. What does being In this group imply about the structure of the nitrogen atom?
sveticcg [70]

Answer:

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Explanation:

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so non-reactive

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