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lubasha [3.4K]
3 years ago
14

There was an airplane crash, every single person on board died, but yet two people survived. How is this possible?

Chemistry
1 answer:
musickatia [10]3 years ago
3 0
They were married so they didn't die! :D hope this helps!
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Calculate the volume of the gas, in liters, if 1.75 mol has a pressure of 1.28 atm at a temperature of -7 ∘C
Alexandra [31]

Answer:

A sample of an ideal gas has a volume of 2.21 L at 279 K and 1.01 atm. Calculate the pressure when the volume is 1.23 L and the temperature is 299 K.

 

You need to apply the ideal gas law PV=nRT

 

You have the pressure, P=1.01 atm

you have the volume, V = 2.21 L

The ideal gas constant R= 0.08205 L. atm/ mole.K at  273 K

 

find n = PV/RT = (1.01 atm x 2.21 L / 0.08205 L.atm/ mole.K x 273 K)

 

n= 0.1 mole, Now find the pressure for n=0.1 mole, T= 299K and

L=1.23 L

 

P=nRT/V= 0.1mole x 0.08205 (L.atm/ mole.K x 299 k)/ 1.23 L

= 1.994 atm

Explanation:

6 0
3 years ago
Write the information obtained from solubility curves.​
salantis [7]

Explanation:

The solubility curve helps us to compare the solubility of difference substances at same temperature. It gives the idea that solubility changes with the temperature. The solubility curve helps us to predict which substance will crystalize out first from hot solution containing two or more solutes.

5 0
3 years ago
HNO3 is an Arrhenius ______________ and increases the concentration of __________ when added to water.
poizon [28]
HNO3 and H2SO4 are Arrhenius acids which will increase the concentration of H+ when dissolved in water.

KOH and Ca(OH)2 are Arrhenius bases that increase the concentration of OH- when dissociated in water.

4 0
3 years ago
Calculate the density of a piece of wood, in the units of g/mL, with a volume of 2.5L and a mass of 12.5 kg
Ganezh [65]

Answer:

5 g / ml

Explanation:

Convert the values given to   g   and ml

12.5 kg = 12500 g

2.5 L = 2500 ml

12500 g / 2500 ml = 5 g/ml

5 0
1 year ago
Calculate the work (kJ) done during a reaction in which the internal volume expands from 20 L to 43 L against an outside pressur
Alenkinab [10]

Answer:

\large \boxed{\text{-10.0 kJ}}

Explanation:

1. Calculate the work

w = - pΔV = -4.3 atm × (43 L - 20 L) = -4.3 × 23 L·atm = -98.9 L·atm

2. Convert litre-atmospheres to joules

w = \text{-98.9 L\cdot$atm } \times \dfrac{\text{101.3 J}}{\text{1 L$\cdot$atm }} = \text{-10000 J} = \textbf{-10.0 kJ}\\\\\text{The work done is $\large \boxed{\textbf{-10.0 kJ}}$}

The negative sign indicates that the work was done against the surroundings.

4 0
3 years ago
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