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3 years ago

Give two uses of nitrogen

Chemistry

1 answer:

jenyasd209 [6]3 years ago

5 0

Answer:

Nitrogen is important to the chemical industry. It is used to make fertilisers, nitric acid, nylon, dyes and explosives. To make these products, nitrogen must first be reacted with hydrogen to produce ammonia.

it is an inert gas, it can be used to replace air and reduce or eliminate oxidation of materials.

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Air in a 0.3 m3 cylinder is initially at a pressure of 10 bar and a temperature of 330K. The cylinder is to be emptied by openin

sergiy2304 [10]

Answer:

(a) Temperature = 330 K, and mass = 0.321 kg

(b) T₂ = 171.56 K, mass = 0.32223 kg

Explanation:

For a constant temperature process we have

p₁v₁ = p₂v₂

Where p₁ = initial pressure = 10 bar = 1000000 Pa

p₂ = final pressure = 1 atm = 101325 Pa

v₁ initial volume = 0.3 m³

v₂ = final volume = unknown

From the relation we have v₂ = 2.96 m³

Therefore at constant temperature 2.93 m³ - 0.3 m³ or 2.66 m³ will be expelled from the container

Temperature = 330 K, and mass =

Also from the relation p1v1 = mRT1

We have, (1000000×0.3)/(8314×330) = 109..337 mole

For air mass

Mass = 3.171 kg

After opening we have

p2v2/(RT1) = n2 = 11.07 mol or 0.321 kg

(b) This is said to be adiabatic condition hence

Here

But cp = 29 (J/mol K).

and p₁v₁ = RT₁ therefore R = 1000000*0.3/330 = 909.1 J/mol·K

And For perfect gas γ = 1.4

Hence T₂ = 171.56 K

γ =cp/cv therefore cv=cp/γ = 29/1.4 = 20.714 (J/mol K). and R =cp-cv = 8.29 J/mol·K

Therefore p1v1/(RT1) = 109.66 moles and we have

p2v2/(R×T2) = 11.11 mole left

For air that is 0.32223 kg

5 0

4 years ago

Methanol (CH3OH) is an organic solvent with a boiling point of 64.5°C. How many grams of mercury(II) bromide (HgBr2, MM = 360.4)

Softa [21]

Answer:

What is the formula for elevation in boiling point?

Explanation:

The elevation in boiling point (ΔTb) is proportional to the concentration of the solute in the solution. It can be calculated via the following equation. Where, i is the Van't Hoff factor.

...

Boiling Point Elevation Formula.

Solvent Kb value (in oC.kg.mol-1)

Chloroform 3.63

Benzene 2.53

3 0

3 years ago

The electron configuration for Zn2 is [Ar] 3d10 and NOT [Ar] 4s23d8. What experimental evidence has been collected that would al

Anna007 [38]

Answer:

Zn2+ is colourless

Explanation:

We know that transition metal salts are usually coloured due to the possibility of d-d transition.

This d-d transition can only occur when there are vacant d-orbitals. The electronic configuration [Ar] 4s23d8 suggests the presence of vacant d-orbitals and the possibility of the compounds of Zn2+ being coloured.

However, the absence of colours in Zn2+ compounds shows that there is no d-d transition(electronic) spectra observed for Zn2+ because the d orbitals are completely filled. This means that the correct electronic configuration of the ion is [Ar] 3d10.

4 0

3 years ago

How many Faradays of electricity are carried by 1.505×10^23 electronsk

aksik [14]

Mole of electron required by $1.505 *10^{23}$ mole is $2.5* 10 ^{-1}$

Faraday law expressed how the change that is been being produced by a current at an electrode-electrolyte interface is related and proportional to the quantity of electricity that is been used.

There is one mole of electron required for 1 Faraday of electricity.

Avogadro constant is $6.02*10^{23}$

Mole of electron can be calculated by dividing the number of electron by avogadro's constant.

= $\frac{1.505*10^{23} }{6.02*10^{23} }$

= $2.5* 10^{-1} Faraday of electricity$

Therefore, it requires $2.5*10^{-1}$ Faraday of electricity for the $1.505 * 10^{23} mole.$

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3 0

2 years ago

An electron on an energy level has an energy of 16.32 x 10-19 J. It moves to another level by releasing 5.4 x 10-19 J of energy.

SVEN [57.7K]

From the information provided in the question, we can see that; the electron moved up to an energy level and has an energy of 21.72 x 10-19 J.

Bohr's model of the atom tells us that electrons are found in certain specific energy levels. Energy is absorbed when an electron moves from a lower to a higher energy level and energy is released when an electron moves from a higher to a lower energy level.

Given that;

ΔE = E2 - E1

E2 = final energy level

E1 = initial energy level

E2 = ?

E1 = 16.32 x 10-19 J

ΔE = 5.4 x 10-19

E2 = ΔE + E1

E2 = 5.4 x 10-19 + 16.32 x 10-19 J

E2 = 21.72 x 10-19 J

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5 0

3 years ago

Give two uses of nitrogen ​

Give two uses of nitrogen