All categories

3 years ago

What is the average speed of a car that moves 570 m in 24 s

1 answer:

7 0

The formula for speed is:
Speed = Distance/Time
We can plug in the given values into the above equation:
Speed = 570m÷24s
Speed = 23.75, which rounds to 24m/s as a whole number. Therefore, the answer is b.

You might be interested in

Help pleasseeee URGENT

Zina [86]

Answer:

The speed of the 8-ball is 2.125 m/s after the collision.

Explanation:

<u>Law Of Conservation Of Linear Momentum</u>

The total momentum of a system of masses is conserved unless an external force is applied. The momentum of a body with mass m and velocity v is calculated as follows:

P=mv

If we have a system of masses, then the total momentum is the sum of all the individual momentums:

$P=m_1v_1+m_2v_2+...+m_nv_n$

When a collision occurs, the velocities change to v' and the final momentum is:

$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

In a system of two masses, the law of conservation of linear momentum is simplified to:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

The m1=0.16 Kg 8-ball is initially at rest v1=0. It is hit by an m2=0.17 Kg cue ball that was moving at v2=2 m/s.

After the collision, the cue ball comes to rest v2'=0. It's required to find the final speed v1' after the collision.

The above equation is solved for v1':

$\displaystyle v'_1=\frac{m_1v_1+m_2v_2-m_2v'_2}{m_1}$

$\displaystyle v'_1=\frac{0.16*0+0.17*2-0.17*0}{0.16}$

$\displaystyle v'_1=\frac{0.34}{0.16}$

$v'_1=2.125\ m/s$

The speed of the 8-ball is 2.125 m/s after the collision.

8 0

3 years ago

A laser pulse takes 2.56 seconds to travel from Earth to the Moon and return. Use this to calculate how far away the Moon is. Ho

Deffense [45]

Answer:

$x = 3.84\times 10^{5}\,km$

This delay affect conversations in the sense that recipient will be receive the message just 2.56 seconds after the message was sent.

Explanation:

The laser pulse has an ondulatory nature as electromagnetic wave, which can travel in the void. Speed of light is constant and distance between Earth and the Moon is:

$x = 0.5\cdot c\cdot \Delta t$

$x = 0.5\cdot (3\times 10^{5}\,\frac{km}{s})\cdot (2.56\,s)$

$x = 3.84\times 10^{5}\,km$

This delay affect conversations in the sense that recipient will be receive the message just 2.56 seconds after the message was sent.

7 0

3 years ago

An asteroid is on a collision course with Earth. An astronaut lands on the rock to bury explosive charges that will blow the ast

forsale [732]

Answer:

The maximum radius the asteroid can have for her to be able to leave it entirely simply by jumping straight up is approximately 1782.45 meters

Explanation:

Whereby the height the astronaut can jump on Earth = 0.500 m, we have the following kinematic equation;

v² = u² - 2·g·h

Where;

v = The final velocity

u = The initial velocity

g = The acceleration due to gravity ≈ 9.8 m/s²

h = The height she jumps

At the maximum height, $h_{max}$ = 0.500 m, she jumps, v = 0, therefore, we have;

0² = u² - 2·g· $h_{max}$

u² = 2 × 9.8 × 0.5 = 9.8

u = √9.8 ≈ 3.13

u = 3.13 m/s

Her initial jumping velocity ≈ 3.13 m/s

Escape velocity, $v_e = \sqrt{\dfrac{2 \cdot G \cdot M}{r} }$

Where;

M = The mass of the asteroid

G = The Universal gravitational constant = 6.67408 × 10⁻¹¹ m³/(kg·s²)

r = The radius of the asteroid

The average density of the Earth = 5515 kg/m³

The mass of the asteroid, M = Density × Volume = 5515 kg/m³× 4/3 × π × r³

The escape velocity, she has, $v_e$ ≈ 3.13 m/s is therefore;

$3.13 = \sqrt{\dfrac{2 \times 6.67408 \times 10^{-11} \times 5515 \times \frac{4}{3} \times \pi \times r^3}{r} } = r \times \sqrt{3.084 \times 10^{-6}}$

$r = \dfrac{3.13}{ \sqrt{3.084 \times 10^{-6}}} \approx 1782.45$

Therefore, the maximum radius of the asteroid can have for her jumping velocity to be equal to the escape velocity for her to be able to leave it entirely simply by jumping straight up = r ≈ 1782.45 meters.

7 0

3 years ago

Camille knows that range of motion is very important. She is designing a weekly exercise program and is not sure where flexibili

klemol [59]

The best activity for her to do to improve her range of motion is flexibility.

<h3>What are a few range of motion illustrations?</h3>

The term the range of motion (ROM) describes the extent to which a joint or muscle may be moved or stretched. Everybody has a distinct experience. For instance, whereas some people can perform a complete split, others cannot because their joints are stiff and their muscles are unable to extend as far.

<h3>What restricts motion range?</h3>

A joint is said to have a restricted range of motion when it cannot move easily and completely in its typical position. A mechanical issue within the joint, swollen tissues around the joint, or pain may restrict motion.

To knoiw more about range of motion visit:

brainly.com/question/13403291

#SPJ1

7 0

1 year ago

An object accelerates at 32 m/s² when a force of 71 N is applied to it. What is the object’s mass? show your work

amid [387]

Answer:

Its answer is 2.21 kg.

Explanation:

F =m × a

71 = m × 32

71 ÷ 32 = m

2.21 kg = m

6 0

3 years ago