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Fantom [35]
3 years ago
13

When you stretch a spring 13 cm past its natural length, it exerts a force of 21 N. What is the spring constant of this spring?

Physics
2 answers:
tiny-mole [99]3 years ago
8 0

Answer:

Explanation:

From Hooke's law, F=-kx

Substistuting the values, 21N= -k 13cm you can ignore the minus sign, since it is there to state that the force is always in the opposite direction of the deformation, and has no influence otherwise, and your constant is 1,6154 *10-2 N/m

ExtremeBDS [4]3 years ago
7 0

Answer:

Spring constant, k = 161.5 N-m

Explanation:

It is given that,

Force on spring, F = 21 N

The spring is stretched 13 cm past its natural length i.e. x = 0.13 m

The Hooke's law gives the relationship between the force and the compression in the spring. Mathematically, it can be written as :

F=-kx

k is spring constant

-ve sign shows the direction of force is opposite

So, k=\dfrac{F}{x}

k=\dfrac{21\ N}{0.13\ m}

k = 161.5 N-m

Hence, this is the required solution.

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Damping is negligible for a 0.135-kg object hanging from a light, 6.30-N/m spring. A sinusoidal force with an amplitude of 1.70
IceJOKER [234]

Answer:

0.72 Hz minimum frequency

Explanation:

When the damping is negligible,Amplitude is given as

A = (F/m)/[\sqrt{(\omega ^{^{2}}-\omega _{o}^{2}})^2

here \omega _{o}^{2}= k/m = (6.30)/(0.135) = 46.67 N/m kg

F / mA = 1.70/(0.135)(0.480) = 26.2 N/m kg

From the above equation , rearranging for ω,

\omega ^{2}= \omega _{o}^{2}\pm F/m

⇒ ω² =46.67 ± 26.2 = 72.87 or 20.47

⇒ ω = 8.53 or 4.52 rad/s

Frequency = f

ω=2 π f

⇒ f = ω / 2π =  8.53 /6.28  or 4.52 / 6.28 = 1.36 Hz or 0.72 Hz

The lower frequency is 0.72 Hz and higher is 1.36 Hz

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3 years ago
Two large, flat, horizontally oriented plates are parallel to each other, a distance d apart. Half-way between the two plates th
fgiga [73]

Answer:

Explanation:

Let the potential difference between the plate is V . Then in the first case

Electric field E between plate

E₁ = V / d

where d is separation between plate

When the plate separation becomes d / 2

Electric field E between plate

E₂ = V / d /2

= 2 V / d =2E₁

Or twice the earlier field

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3 years ago
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How big is the image produced by the periscope compared to the size of the object
ipn [44]

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<span>Put a lens in the middle of the tube </span>

<span>? </span>

<span>We use mirrors when we drive cars ect </span>

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3 years ago
The morning of a birthday party, a balloon is filled with 8.5 L of helium (He) when the temperature is 294 kelvin. The party sta
Phoenix [80]

Explanation:

the morning of the birthday party balloon filled with the 2.5 Litre of helium

temperature is 294kelvin

the party starts at the 4 p.m.

temperature rises 305 Kelvin.

the new volume = 4 litre.

At same temperature,

P

1

V

2

=P

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P

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V

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But while filling balloons from cylinder when pressure in cylinder becomes 1 atm then further filling is not possible (P

1

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=9atm)

Let n be the number of balloons that can be filled.

∴P

1

′

V

1

=n(P

1

V

1

)

9×8=n(4×1)

n=

4

9×8

=18balloons

5 0
3 years ago
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