When you stretch a spring 13 cm past its natural length, it exerts a force of 21 N. What is the spring constant of this spring?
2 answers:
Answer:
Explanation:
From Hooke's law,
Substistuting the values, you can ignore the minus sign, since it is there to state that the force is always in the opposite direction of the deformation, and has no influence otherwise, and your constant is
Answer:
Spring constant, k = 161.5 N-m
Explanation:
It is given that,
Force on spring, F = 21 N
The spring is stretched 13 cm past its natural length i.e. x = 0.13 m
The Hooke's law gives the relationship between the force and the compression in the spring. Mathematically, it can be written as :
k is spring constant
-ve sign shows the direction of force is opposite
So,
k = 161.5 N-m
Hence, this is the required solution.
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Answer:
The work done by a particle from x = 0 to x = 2 m is 20 J.
Explanation:
A force on a particle depends on position constrained to move along the x-axis, is given by,
We need to find the work done on a particle that moves from x = 0.00 m to x = 2.00 m.
We know that the work done by a particle is given by the formula as follows :
So, the work done by a particle from x = 0 to x = 2 m is 20 J. Hence, this is the required solution.