All categories

3 years ago

When you stretch a spring 13 cm past its natural length, it exerts a force of 21 N. What is the spring constant of this spring?

Physics

2 answers:

tiny-mole [99]3 years ago

8 0

Answer:

Explanation:

From Hooke's law, $F=-kx$

Substistuting the values, $21N= -k 13cm$ you can ignore the minus sign, since it is there to state that the force is always in the opposite direction of the deformation, and has no influence otherwise, and your constant is $1,6154 *10-2 N/m$

ExtremeBDS [4]3 years ago

7 0

Answer:

Spring constant, k = 161.5 N-m

Explanation:

It is given that,

Force on spring, F = 21 N

The spring is stretched 13 cm past its natural length i.e. x = 0.13 m

The Hooke's law gives the relationship between the force and the compression in the spring. Mathematically, it can be written as :

$F=-kx$

k is spring constant

-ve sign shows the direction of force is opposite

So, $k=\dfrac{F}{x}$

$k=\dfrac{21\ N}{0.13\ m}$

k = 161.5 N-m

Hence, this is the required solution.

You might be interested in

A child is playing on a swing. As long as he does not swing too high the time it takes him to complete one full oscillation will

Aleks [24]

Answer:

We know that for a pendulum of length L, the period (time for a complete swing) is defined as:

T = 2*pi*√(L/g)

where:

pi = 3.14

L = length of the pendulum

g = gravitational acceleration = 9.8 m/s^2

Now, we can think on the swing as a pendulum, where the child is the mass of the pendulum.

Then the period is independent of:

The mass of the child

The initial angle

Where the restriction of not swing to high is because this model works for small angles, and when the swing is to high the problem becomes more complex.

7 0

3 years ago

A 2.2-kg block slides on a horizontal surface with a speed of v=0.80m/s and an

mina [271]

Answer:

μ = 0.33

Equal to 3.2 m/s²

Explanation:

Draw a free body diagram of the block. There are three forces:

Normal force N pushing up.

Weight force mg pulling down.

Friction force Nμ pushing opposite the direction of motion.

Sum of forces in the y direction.

∑F = ma

N − mg = 0

N = mg

Sum of forces in the x direction.

∑F = ma

Nμ = ma

Substitute.

mgμ = ma

μ = a/g

μ = (3.2 m/s²) / (9.8 m/s²)

μ = 0.33

As found earlier, the acceleration is a = gμ. Since g and μ are constant, a is also constant, so it does not change with velocity.

5 0

3 years ago

A drag racer starts from rest and accelerates at 10 m/s squared for the

nika2105 [10]

Answer:

54 $\frac{m}{s}$

Explanation:

$v=u+at$

where $u=$ initial velocity

$v=0+(10\frac{m}{s^{2} } )$ × $(5.4s)$

$v=54\frac{m}{s}$

6 0

3 years ago

Which describes the molecular motion of a solid nickel marble rolled across the floor?

Gemiola [76]

I can't decide between A and B, but B seems more likely to me. Even though the molecules don't look like they're moving, the area of contact is slightly more compressed.

7 0

3 years ago

Mga tanong 1. Ano ang nangyari sa lobo? 2. Sa iyong palagay, saan napunta ang pumutok na lobo? 3. Kapag pumutok ang lobo ano ang

gavmur [86]

Answer:

1. Pumutok ang Lobo

2.basurahan

3.may kwentong po ba to paano ko masagot ng wala naman akong mababasang kwento :) :) :)

4 0

2 years ago