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3 years ago

When two objects collide, the momentum of the system remains constant. This is a statement of ______________.

Physics

2 answers:

Gennadij [26K]3 years ago

7 0

Answer:

B. Newton's third law

Explanation:

When two bodies collide the moment remains constant.

This occurs because we define a system that is formed by the two bodies, so that the forces last = before the shock are forces of action and reaction, from one body to the other, so that for the system (two bodies) the force total is zero, we assume that the system is isolated from the outside.

In summary, the initial establishment is a consequence of Newton's third law

Fudgin [204]3 years ago

3 0

Conservation of momentum

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3 years ago

What it means to say that energy is conserved as a ball fall towards ground

stiv31 [10]

Mechanical energy = Potential Energy + Kinetic Energy

if there is no friction, M.E. is conserved
as a ball falls, it is losing height. (P.E.=mgh , therefore P.E. will decrease)

the potential energy is transformed into kinetic energy which equals 1/2MV^2.

the increase in K.E. equals the decrease in P.E.

and the sum of both equals M.E.

thus mechanical energy is conserved.

hope this helps you.

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3 years ago

how much heat energywill b needed to change the temperature of 275g of parrafin oil by 75k. specific heat capacity of paraffin o

denis-greek [22]

Answer:

43,931,250J

Explanation:

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7 0

3 years ago

Two forces F1 and F2 are lifting a heavy bucket vertically upward. The mass of the bucket is 7.5 kg. The magnitude of F2 = 88 N.

Yuliya22 [10]

Answer:

a) W= 73.5 N

b) F₁ = 97.36 N

c) F₁y= 55.84 N

d) ay = 2.60 m/s²

Explanation:

We apply Newton's second law:

∑F = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in m/s²

Look at the attached graphic

Free body diagram of the bucket

α= 35° : angle that forms F₁ with the x axis

β = 180 -155= 25° :angle that forms F₂ with the x axis

F₂= 88N

m=7.5 kg : mass of the bucket

g= 9.8 m/s² : acceleration due to gravity

a) W: weight of the bucket

W = m*g = 7.5*9.8

W= 73.5 N

b)Equation involving magnitudes of F1. Solve for F1

∑Fx = m *ax ax: acceleration in x , ax=0 ,

F₁* cosα- F₂*cosβ= 0

F₁* cos35° = F₂*cos25°

F₁ = (88*cos25°)/( cos35°)

F₁ = 97.36 N

c) F₁y : the y-component of force vector F₁

F₁y= 97.36* sin35°

F₁y= 55.84 N

d) ay : acceleration in y

∑Fy = m *ay

F₁* sinα+F₂*sinβ -W= m *ay

97.36* sin35°°+88*sin25° -73.5= 7.5 *ay

19.53 = 7.5 *ay

ay = (19.53) / (7.5)

ay = 2.60 m/s²

7 0

3 years ago

if you were to throw a large log over the edge of the grand canyon and took 5.65 seconds to hit the ground, calculate the veloci

worty [1.4K]

Okay assuming the log had no initial vertical motion (you threw it straight out), the distance to the bottom is

dist = 1/2 gt^2 = 1/2 x 9.8m/s/s x
(5.65s)^2 = 156.4m

the velocity at the bottom = g t = 9.m/s/s x 5.65s =55.4m/s

Hope this helps!

8 0

2 years ago

Read 2 more answers