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FrozenT [24]
3 years ago
5

Help please suffering

Physics
1 answer:
inessss [21]3 years ago
3 0

Assuming Lin jumps from and returns to the same level ground, the fact that he stays in the air for 0.8 seconds means it takes him 0.4 seconds to reach his maximum height, at which point his vertical velocity will be 0.

Acceleration is a constant g in the downward direction, and when it's constant it's the same as the average acceleration over any given time interval. Over the 0.4 second interval during which he reaches his maximum height, we have

a_{\rm avg}=-g=\dfrac{0-v_0}{0.4\,\rm s}\implies v_0=3.9\,\dfrac{\rm m}{\rm s}

which is also the same speed he will have when he returns to the ground.

To find the maximum height, we have

0^2-{v_0}^2=2(-g)y_{\rm max}\implies y_{\rm max}=0.78\,\rm m

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Suppose the battery in a clock wears out after moving thousand coulombs of charge through the clock at a rate of 0.5 Ma how long
Ksivusya [100]

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Hello your question is poorly written below is the complete question

Suppose the battery in a clock wears out after moving Ten thousand coulombs of charge through the clock at a rate of 0.5 Ma how long did the clock run on does battery and how many electrons per second slowed?

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a) 231.48 days

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2 years ago
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Mariulka [41]

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Double replacement reaction: elements in two compounds replace each other.

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6 0
3 years ago
Read 2 more answers
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