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Varvara68 [4.7K]
3 years ago
10

Megan and Heidi are making cookies for an upcoming bake sale. Megan is making chocolate chip cookies and Heidi is making sugar c

ookies. If Megan plans to make x bags of cookies, the equation below represents the total number of cookies she will need to make. y= 8x
Heidi recorded the total number of cookies she would need to make in the table.
Bags Total Number
of Cookies
10 50
12 60
14 70
16 80
If Megan and Heidi make the same number of bags of cookies, who will have to make the least amount of cookies?
Mathematics
1 answer:
koban [17]3 years ago
7 0

Answer:

Heidi (260 cookies)

Step-by-step explanation:

Megan's equation is given as y=8x, where x is the number of bags, and y the number of cookies:

#First calculate Heidi's total number of bags, cookies and cookies:

H_b=\sum{bags}\\\\=10+12+14+16\\\\=52 \ bags\\\\H_c=\sum{cookies}\\\\=50+60+70+80\\\\=260 \ cookies

#Given that both Heidi and Megan make the same number of bags of cookies, Megan's cookies totals to:

H_b=M_B=52 \ Bags\\\\M_c=y=8x, x=52\\\\y=8\times 52\\\\=416\\

Hence, Megan makes 416 cookies.

#From our calculations:

416>260\\\\M_c>H_c

Hence, Heidi makes the least number of cookies(260 cookies) compared to Megan's 416 cookies.

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3 years ago
Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi
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Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

5 0
3 years ago
A. x-int:-0.5,y-int:1<br>B. x-int:0.5,y-int:1<br>C. x-int:-0.5,y-int:-1<br>D. x-int:1,y-int:0.5
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The correct answer is:  [D]:  " <span>x-int : 1 ,  y-int:  0.5  " .
_____________________________________________________
Note:
_____________________________________________________
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In other words, what is (are) the point(s) of the graph at which "x = 0<span>" ?
</span>
By examining the graph, we see that when " x = 0" ; y is equal to:  "1<span>" .
</span>
So; the "x-intercept" is at point:  "(0, 1)" ; or, we can simply say that the 
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_________________________________________________________</span>  Note:
_____________________________________________________
The "y-intercept" refers to the point(s) at which the the graph of a function (which is a line, in this case) cross(es) the "x-axis".  

In other words, what is (are) the point(s) of the graph at which " y = 0 <span>" ?
</span>
By examining the graph, we see that when " y = 0 " ; x  is equal to:  "0.5<span>" .
</span>
So; the "x-intercept" is at point:  "(0.5, 0)" ; or, we can simply say that the 
   "y-intercept" is:  "0.5 " .<span>
______</span>_________________________________________________
This would correspond to:<span>
_______________________________________________________
           Answer choice:  [D]:  </span>" x-int: 1 , y-int: 0.5  " .
_______________________________________________________
     {that is;  The "x-intercept" is: "0" ; and the "y-intercept" is:  "0.5 ".} .
_______________________________________________________
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