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mel-nik [20]
3 years ago
15

If you were to take several random samples from a pure substance the samples

Chemistry
2 answers:
faltersainse [42]3 years ago
6 0

Answer:

If you were to take several random samples from a pure substance the samples would be identical.

Explanation:

A pure substance is homogeneous (that means its composition and properties are the same in every part of the substance), therefore the samples would be identical.

Nataliya [291]3 years ago
3 0
Would all have the same ratio of elements.
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Write the balanced equation fr this chemical reaction _Mg + _O2 -> _MgO​
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Answer:

_2Mg + _O2 --≥2MgO this is balanced

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2 years ago
Isotopes do not have the same number of which of these?
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Isotopes are basically from the same element. In terms of subatomic particles of the element, the isotopes will then basically have the same number of protons. The electrons also have to be same in number given that the elements are in neutral charges. 

We are then left with neutrons, which is one of the subatomic particles residing in the nucleus of an atom.

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3 years ago
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The low-grade iron ore taconite, which contains Fe3O4, is concentrated and made into pellets for processing. If one ton of tacon
xenn [34]

<u>Answer:</u> The percent composition of Fe_3O_4 in taconite is 37.6 %.

<u>Explanation:</u>

We are given:

Mass of taconite pellets = 1 ton = 907185 g      (Conversion factor: 1 ton = 907185 g)

Mass of iron produced = 545 lb = 247212 g    (Conversion factor:  1 lb = 453.6 g )

We know that:

Molar mass of iron = 55.85 g/mol

Molar mass of Fe_3O_4 = 231.53 g/mol

1 mole of Fe_3O_4 contains 3 moles of iron atom and 4 moles of oxygen atom

(3 × 55.85) = 167.55 g of iron is produced from 231.53 grams of Fe_3O_4

So, 247212 grams of iron will be produced from = \frac{231.53}{167.55}\times 247212=341611.43g of Fe_3O_4

To calculate the percentage of Fe_3O_4 in taconite, we use the equation:

\%\text{ composition of }Fe_3O_4=\frac{\text{Mass of }Fe_3O_4}{\text{Mass of taconite}}\times 100

Mass of taconite = 907185 g

Mass of Fe_3O_4 = 341611.43 g

Putting values in above equation, we get:

\%\text{ composition of }Fe_3O_4=\frac{341611.43g}{907185g}\times 100=37.6\%

Hence, the percent composition of Fe_3O_4 in taconite is 37.6 %.

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3 years ago
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murzikaleks [220]

Answer: Well!

Explanation: I was going to answer D but fverdell82156 got to it first! So I have to agree with him! It is D!

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3 years ago
Can an ion be either positive or negative? True or False
vekshin1

Answer:

True

Explanation:

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3 years ago
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