Answer:
Percent yield of CO₂ is 6.25 %.
Explanation:
Given data:
Percent yield of CO₂ = ?
Actual yield of CO₂ = 28.16 g
Number of moles of C₈H₁₈ = 8.000 mol
Number of moles of O₂ = 16.00 mol
Solution:
Chemical equation:
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
Now we will compare the moles of C₈H₁₈ and O₂ with CO₂.
C₈H₁₈ : CO₂
2 : 16
8.000 : 16/2×8.000 = 64 mol
O₂ : CO₂
25 : 16
16 : 16/25×16= 10.24 mol
Less number of moles of CO₂ are produced from 16 moles of O₂. it will limit the yield of CO₂.
Grams of CO₂ produced:
Mass = number of moles × molar mass
Mass = 10.24 mol × 44 g/mol
Mass = 450.56 g
Percentage yield of CO₂:
Percentage yield = actual yield / theoretical yield × 100
Percentage yield = 28.16 g/ 450.56 g× 100
Percentage yield = 6.25 %
Answer:
--Acid is the substance when dissolved in water, increases the concentration of H+ ions.
--Such compound whose chemical formula begins with H, for example HCl (Hydrochloric acid), H3BO3 (Boric acid), CH2O3 (Carbonic
acid). Although CH3COOH (Acetic acid) is an exception.
--Its less than 7.
--Bases are the proton acceptor.
--Such compounds whose chemical formula ends with OH, for example KOH (Potassium hydroxide), NaOH (Sodium hydroxide).
--Its greater than 7.
Explanation:
Answer: Group 16 elements form ions with a 2 - charge.
Explanation: Therefore each of these elements would gain one electron and become an anion with 1 - charge.
They rarely occur at molecular levels is incorrect, actually they always occur at molecular levels