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LuckyWell [14K]
3 years ago
15

SO2Cl2 decomposes in a first-order process with a half-life of 4.88 × 103 s. If the original concentration of SO2Cl2 is 0.011 M,

how many seconds will it take for the SO2Cl2 to reach 0.0032 M?
Chemistry
1 answer:
DiKsa [7]3 years ago
5 0
The amount of substance after n half-lives is calculated through the equation,
                                     A(n) = A(0) x (0.5)^t/h
where A(n) is the amount of n half-lives, A(0) is the original amount, t is the total time and h is the half-life. 
Substituting the known values,
 Basis is 1L,
                           0.0032 = (0.011) x (0.5)^(t/4.88x10^3s)
The value of t from the generated equation is equal to 8693.0 s or also equal to 8.693 x 10^3 s. 
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p_{A} =9.98g/10.00mL=0.998g/mL\\p_{B} =15.61g/15.00mL=1.041g/mL\\p_{C} =25.65g/25.00mL=1.026g/mL

  • (2)To calculate the average density, we add each density and divide the result by the number of experiments (in this case 3):

p_{average}=\frac{p_{1}+p_{2}+p_{3}}{3}   \\p_{average}=\frac{(0.998+1.041+1.026)g/mL}{3}\\p_{average}=1.022g/mL

  • (3) The percent error is calculated by dividing the absolute value of the substraction of the theorethical and experimental values, by the theoretical value, times 100:

%error=\frac{|p_{average}-p_{theoretical}|}{p_{theoretical}} *100

%error=\frac{|1.022g/mL-0.997655g/mL|}{0.997655g/mL}*100

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The energy of the photon from the calculation performed is 3.5 * 10^-16 J.

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A photon is a packet of light. It was derived from the theory of Albert Einstein. The energy of a photon is obtained from; E = hc/λ

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E = 3.5 * 10^-16 J

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2 years ago
While finding the number of molecules of oxygen molecules present in 3.65 moles of Na2SO4 the conversion factor used would be
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