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4 years ago

What are the main forms of energy? Define each type

1 answer:

4 0

Thermal energy - the internal kinetic energy in a substance caused by vibration of atoms and molecules. Thermal energy is also known as heat.

Radiant energy - is the electromagnetic energy that travels in waves. Radiant energy is kinetic energy that includes light, x-rays, microwaves, and radio waves.

Elastic energy - potential energy produced from stored or released elastic materials. This is stored mechanical energy energy resulting from being stretched or compressed.

Mechanical energy - the energy an object possesses due to movement. Mechanical energy is kinetic energy because it is the movement from one position to another.

Gravitational energy - the potential energy an object has because of position. This is produced from gravitational force acting upon an object.

Chemical energy - the potential energy stored in the bonds of molecules and compounds.

Nuclear energy - potential energy stored in the core (nucleus) of an atom.

Electrical energy - the kinetic energy produced from the movement of an electric charge.

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Does ammonification increase or decrease biomass? How?

Stels [109]

Hello! I'm not too knowledgeable on this topic, but I do know that ammonification is caused through different inorganic reactions. Or to metabolism systems of organisms. I also found it is a process in which nitrate reduction to nitrite is followed by the six-electron reduction of nitrite to ammonium.

5 0

3 years ago

When you push a 1.85-kg book resting on a

Margaret [11]

Answer:

Given:

mb=2.05 kgmb=2.05 kg Mass of the book

fs=2.45 Nfs=2.45 N Static friction

fk=1.50 Nfk=1.50 N Kinetic friction

6 0

3 years ago

A point charge Q is held at a distance r from the center of a dipole that consists of two charges ±qseparated by a distance s. T

atroni [7]

Answer:

The magnitude of the force on the dipole due to the charge Q = $\rm \dfrac{1}{\epsilon_o}\times \dfrac{1}{4\pi }\dfrac{2qQs}{r^3}.$

The magnitude of the torque on the dipole = $\rm \dfrac{1}{\epsilon_o}\times \dfrac{1}{4\pi}\dfrac{2qQs^2}{r^3}.$

Explanation:

Given that a point charge Q is held at a distance r from the center of a dipole that consists of two charges ±q, separated by a distance s and the charge Q is located in the plane that bisects the dipole.

The magnitude of the electric field that the dipole exerts at the position where the charge Q is held is given by

$\rm E = \dfrac{k2qs}{(r^2+s^2)^{3/2}}.$

<em>where</em>,

k is the Coulomb's constant, having value = $\dfrac{1}{4\pi \epsilon_o}$

$\epsilon_o$ is the electrical permittivity of free space.

Also, r>>s, therefore, $\rm r^2+s^2\approx r^2.$

$\rm E = \dfrac{k2qs}{(r^2)^{3/2}}=\dfrac{k2qs}{r^3}.$

The magnitude of the electric force F on a charge q placed at a point and the magnitude of the electric field E at that point are related as

$\rm F=qE$

Therefore, the electric force on the charge Q due to the dipole is given by

$\rm F=Q\dfrac{k2qs}{r^3}=\dfrac{1}{4\pi \epsilon_o}\dfrac{2qQs}{r^3}.$

According to Newton's third law of motion, the magnitude of the force exerted by the dipole on the charge Q is same as the magnitude of the force exerted by the charge on the dipole.

Thus, the magnitude of the force on the dipole due to the charge Q = $\dfrac{1}{\epsilon_o}\times \dfrac{1}{4\pi }\dfrac{2qQs}{r^3}.$

The magnitude of the torque on the dipole is given by

$\rm \tau = Fs\ \sin\theta$

Since the charge Q is placed in the plane that bisects the dipole, therefore, $\theta = 90^\circ$ .

$\rm \tau = \dfrac{1}{4\pi \epsilon_o}\dfrac{2qQs}{r^3}\cdot s\cdot 1=\dfrac{1}{4\pi \epsilon_o}\dfrac{2qQs^2}{r^3}.$

4 0

3 years ago

A conductor carrying 14.7 amps of current is directed along the positive x-axis and perpendicular to a uniform magnetic field. A

Gnoma [55]

Explanation:

It is given that,

Current carried in the conductor, I = 14.7 A (+x axis)

The magnetic force per unit length on the conductor, $\dfrac{F}{L}=0.125\ N/m$ (-y axis)

The magnetic force is given by :

$F=ILBsin\theta$

$\theta=90$

$F=ILB$

$B=\dfrac{F}{IL}$

$B=\dfrac{0.125}{14.7}$

B = 0.0085 T

According to right hand rule, the direction of magnetic force can be calculated. So, the direction of magnetic field is along +z axis. Hence, this is the required solution.

4 0

3 years ago

This problem has been solved!

AleksAgata [21]

Answer:the velocity is zero, the acceleration is directed downward, and the force of gravity acting on the ball is directed downward.

Explanation:

When a ball is tossed vertically upwards, it reaches its maximum point. This maximum point is known as the maximum height of the ball. At this maximum height, its velocity is zero, its acceleration is directed downwards and the force of gravity acting in the ball is directed downwards towards the earth.

6 0

3 years ago